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# If two sets of numbers , P and Q, have the same number of

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Intern
Joined: 23 Aug 2009
Posts: 17
Followers: 0

Kudos [?]: 8 [0], given: 8

If two sets of numbers , P and Q, have the same number of [#permalink]  02 Dec 2009, 00:16
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If two sets of numbers , P and Q, have the same number of elements, is the mean of set Q lower than the mean of set P?

a. Set Q consists of consecutive even integers and set P of consecutive odd integers.

b. The median of set Q is higher than the mean of set P.

Am i correct?
_________________

Peace

Joined: 20 Aug 2009
Posts: 312
Location: Tbilisi, Georgia
Schools: Stanford (in), Tuck (WL), Wharton (ding), Cornell (in)
Followers: 14

Kudos [?]: 98 [0], given: 69

Re: Mean and median [#permalink]  02 Dec 2009, 05:22
For consecutive integers mean=median so Statement 2 is sufficient.

(B)
Intern
Joined: 23 Aug 2009
Posts: 17
Followers: 0

Kudos [?]: 8 [0], given: 8

Re: Mean and median [#permalink]  02 Dec 2009, 09:01
Statement 2 does not say anything about consecutive integers.
_________________

Peace

Joined: 20 Aug 2009
Posts: 312
Location: Tbilisi, Georgia
Schools: Stanford (in), Tuck (WL), Wharton (ding), Cornell (in)
Followers: 14

Kudos [?]: 98 [0], given: 69

Re: Mean and median [#permalink]  02 Dec 2009, 10:26
ro86 wrote:
Statement 2 does not say anything about consecutive integers.

You're right. We need Statement 1 too.
SVP
Joined: 29 Aug 2007
Posts: 2497
Followers: 57

Kudos [?]: 551 [0], given: 19

Re: Mean and median [#permalink]  05 Dec 2009, 10:44
ro86 wrote:
If two sets of numbers , P and Q, have the same number of elements, is the mean of set Q lower than the mean of set P?

a. Set Q consists of consecutive even integers and set P of consecutive odd integers.
b. The median of set Q is higher than the mean of set P.

Am i correct?

C. Both statements are required to make sure that median of set Q > median of set P.
_________________
Re: Mean and median   [#permalink] 05 Dec 2009, 10:44
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