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Re: if u > t, r > q, s > t, and t > r, which of the following [#permalink]
31 Oct 2012, 12:05
from the question we can establish u - t > 0, r - q > 0, s - t > 0, and t - r > 0 (u - t) + (t -r ) >0 ==> u > r III holds (r - q) +(t - r) > 0 ==> t > q Since s > t and t > q ==> s > q II holds Brother Karamazov
Re: If u > t, r > q, s > t, and t > r, which of the following [#permalink]
26 Dec 2015, 01:14
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