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If v and W are diffferent integers, does v=0

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If v and W are diffferent integers, does v=0 [#permalink] New post 02 Mar 2010, 14:43
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A
B
C
D
E

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Hi

the two questions 122 and 126 are kind of ambiguous(answers actually)

let me put question here

Q122). If v and W are diffferent integers, does v=0

A) vw=vexp2
B)w=2

for me the answer should be D. Whereas the answer is A. Please explain.

Q126) if zexpn=1 what is the value of Z.
A) n is a non zero ineger
B) Z>0

answer given is C. My answer is A. Please explain.

Thanks
Sach
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Re: OG 11th edition - DS - 122 and 126 [#permalink] New post 02 Mar 2010, 15:50
willisback wrote:
Q122). If v and W are diffferent integers, does v=0

A) vw=vexp2
B)w=2


st 1) vw - v^2 = 0
v(w-v) = 0
V=0 as w-v cannot be zero as v,w are different integers.
st 2) w=2 . Not sufficient

A
(Dont use the information given in statement 1 in statement 2 as st 2 just said w=2 and nothing about v)
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Re: OG 11th edition - DS - 122 and 126 [#permalink] New post 02 Mar 2010, 15:59
willisback wrote:

Q126) if z^n=1 what is the value of Z.
A) n is a non zero ineger
B) Z>0


st 1) n!=0
z=-1, n = 2, z^n=1
z=1, n = 1, z^n=1
Not sufficient
st 2) z>0
Not sufficient
combining z=1

C
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Re: OG 11th edition - DS - 122 and 126 [#permalink] New post 03 Mar 2010, 11:47
willisback wrote:
Hi

the two questions 122 and 126 are kind of ambiguous(answers actually)

let me put question here

Q122). If v and W are diffferent integers, does v=0

A) vw=vexp2
B)w=2

for me the answer should be D. Whereas the answer is A. Please explain.


Given: v # w (not equal to)
Is v = 0?
A: vw = v^2
v(w-v) = 0, which means either v =0 or v = w... but since it's given v # w, this mean v = 0. Hence SUFF

B: w = 2
v could be anything but 2.... hence NOT SUFF....

Therefore A.

willisback wrote:
Q126) if zexpn=1 what is the value of Z.
A) n is a non zero ineger
B) Z>0

answer given is C. My answer is A. Please explain.

Thanks
Sach


given z^n = 1
ques: z = ?

A) n # 0 .
Hence z^n = 1 means z can be -1 or +1 because (-1)^2 = 1 and (1)^2 = 1. Hence Not SUFF

B) z>0
Not Suff... as z could be anything.

A+B = SUFF as now z can only be 1 if n # 0.

Therefore C.
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Re: OG 11th edition - DS - 122 and 126   [#permalink] 03 Mar 2010, 11:47
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