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If vmt ? 0, is v2m3t-4 > 0? (1) m > v2 (2) m

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If vmt ? 0, is v2m3t-4 > 0? (1) m > v2 (2) m [#permalink] New post 20 May 2007, 19:40
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C
D
E

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1.If vmt ≠ 0, is v2m3t-4 > 0?
(1) m > v2
(2) m > t-4
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

2.
What is the value of (x - y)4?
(1) The product of x and y is 7.
(2) x and y are integers.

3.
Mary persuaded n friends to donate $500 each to her election campaign, and then each of these n friends persuaded n more people to donate $500 each to Mary’s campaign. If no one donated more than once and if there were no other donations, what was the value of n?
(1) The first n people donated 161 of the total amount donated.
(2) The total amount donated was $120,000.

4.
If x and y are positive, is x3 > y?
(1) x > y

(2) x > y

5.
Tom, Jane, and Sue each purchased a new house. The average (arithmetic mean) price of the three houses was $120,000. What was the median price of the three houses?
(1) The price of Tom’s house was $110,000.
(2) The price of Jane’s house was $120,000.
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Re: Old GMAT DS problems [#permalink] New post 20 May 2007, 19:49
bhaarat wrote:
1.If vmt ≠ 0, is v2m3t-4 > 0?
(1) m > v2
(2) m > t-4


v^2m^3t^-4 > 0? => m > 0?

(1) m > v^2 > 0 => suff

(2) m > t^-4 >0 => suff

Hence, (D)
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Re: Old GMAT DS problems [#permalink] New post 20 May 2007, 19:55
bhaarat wrote:
5.
Tom, Jane, and Sue each purchased a new house. The average (arithmetic mean) price of the three houses was $120,000. What was the median price of the three houses?
(1) The price of Tom’s house was $110,000.
(2) The price of Jane’s house was $120,000.


(B) it is

T + J + S = 120,000 x 3 = 360,000

(1) T = 110,000 => J + S = 250,000
=> Can not figure out the median => insuff

(2) J = 120,000 => T + S = 240,000
=> The median is 120,000 in all possible cases => suff

Hence, (B)
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Re: Old GMAT DS problems [#permalink] New post 20 May 2007, 19:57
bhaarat wrote:
4.
If x and y are positive, is x3 > y?
(1) x > y

(2) x > y



Something wrong with this question. BTW, from (1) only, insuff
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Re: Old GMAT DS problems [#permalink] New post 20 May 2007, 20:04
bhaarat wrote:
2.
What is the value of (x - y)4?
(1) The product of x and y is 7.
(2) x and y are integers.



(C) it is

(x - y)^4 ?

(1) xy = 7 => insuff

(2) If x and y = intergers => insuff


(1) and (2):

=> case 1: x = 7 and y = 1 => (x - y)^4 = 6^4
=> or case 2: x = 1 and y = 7 => (x - y)^4 = 6^4

=> suff
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 [#permalink] New post 21 May 2007, 06:31
bhaarat wrote:

5.
Tom, Jane, and Sue each purchased a new house. The average (arithmetic mean) price of the three houses was $120,000. What was the median price of the three houses?
(1) The price of Tom’s house was $110,000.
(2) The price of Jane’s house was $120,000.

kirakira wrote:
(B) it is

T + J + S = 120,000 x 3 = 360,000

(1) T = 110,000 => J + S = 250,000
=> Can not figure out the median => insuff

(2) J = 120,000 => T + S = 240,000
=> The median is 120,000 in all possible cases => suff

Hence, (B)

Many thanks for posting your reply. Answer is B ,but i am still not sure why B is suff. If T and S are 110,000 and 130,000 respectively, then also T+S= 240,000; Isn't it? Am i missing something here?
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 [#permalink] New post 21 May 2007, 09:51
isn't 'median' mean middle

so if it is

$110,000
$120,000
$130,000

you still get $120,000 as the median. You're trying to find the middle of the three not the mean.

(am i off here?!?!? :)
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 [#permalink] New post 21 May 2007, 11:59
gowani wrote:
isn't 'median' mean middle

so if it is

$110,000
$120,000
$130,000

you still get $120,000 as the median. You're trying to find the middle of the three not the mean.

(am i off here?!?!? :)

Gowani,
You are right.
Thanks,
Bharat
  [#permalink] 21 May 2007, 11:59
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