Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 30 Aug 2015, 06:07

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If vmt ? 0, is v2m3t-4 > 0? (1) m > v2 (2) m

Author Message
Manager
Joined: 26 Aug 2006
Posts: 55
Followers: 1

Kudos [?]: 0 [0], given: 29

If vmt ? 0, is v2m3t-4 > 0? (1) m > v2 (2) m [#permalink]  20 May 2007, 19:40
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

1.If vmt ≠ 0, is v2m3t-4 > 0?
(1) m > v2
(2) m > t-4
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

2.
What is the value of (x - y)4?
(1) The product of x and y is 7.
(2) x and y are integers.

3.
Mary persuaded n friends to donate $500 each to her election campaign, and then each of these n friends persuaded n more people to donate$500 each to Mary’s campaign. If no one donated more than once and if there were no other donations, what was the value of n?
(1) The first n people donated 161 of the total amount donated.
(2) The total amount donated was $120,000. 4. If x and y are positive, is x3 > y? (1) x > y (2) x > y 5. Tom, Jane, and Sue each purchased a new house. The average (arithmetic mean) price of the three houses was$120,000. What was the median price of the three houses?
(1) The price of Tom’s house was $110,000. (2) The price of Jane’s house was$120,000.
Manager
Joined: 02 May 2007
Posts: 152
Followers: 1

Kudos [?]: 5 [0], given: 0

Re: Old GMAT DS problems [#permalink]  20 May 2007, 19:49
bhaarat wrote:
1.If vmt ≠ 0, is v2m3t-4 > 0?
(1) m > v2
(2) m > t-4

v^2m^3t^-4 > 0? => m > 0?

(1) m > v^2 > 0 => suff

(2) m > t^-4 >0 => suff

Hence, (D)
Manager
Joined: 02 May 2007
Posts: 152
Followers: 1

Kudos [?]: 5 [0], given: 0

Re: Old GMAT DS problems [#permalink]  20 May 2007, 19:55
bhaarat wrote:
5.
Tom, Jane, and Sue each purchased a new house. The average (arithmetic mean) price of the three houses was $120,000. What was the median price of the three houses? (1) The price of Tom’s house was$110,000.
(2) The price of Jane’s house was $120,000. (B) it is T + J + S = 120,000 x 3 = 360,000 (1) T = 110,000 => J + S = 250,000 => Can not figure out the median => insuff (2) J = 120,000 => T + S = 240,000 => The median is 120,000 in all possible cases => suff Hence, (B) Manager Joined: 02 May 2007 Posts: 152 Followers: 1 Kudos [?]: 5 [0], given: 0 Re: Old GMAT DS problems [#permalink] 20 May 2007, 19:57 bhaarat wrote: 4. If x and y are positive, is x3 > y? (1) x > y (2) x > y Something wrong with this question. BTW, from (1) only, insuff Manager Joined: 02 May 2007 Posts: 152 Followers: 1 Kudos [?]: 5 [0], given: 0 Re: Old GMAT DS problems [#permalink] 20 May 2007, 20:04 bhaarat wrote: 2. What is the value of (x - y)4? (1) The product of x and y is 7. (2) x and y are integers. (C) it is (x - y)^4 ? (1) xy = 7 => insuff (2) If x and y = intergers => insuff (1) and (2): => case 1: x = 7 and y = 1 => (x - y)^4 = 6^4 => or case 2: x = 1 and y = 7 => (x - y)^4 = 6^4 => suff Manager Joined: 26 Aug 2006 Posts: 55 Followers: 1 Kudos [?]: 0 [0], given: 29 [#permalink] 21 May 2007, 06:31 bhaarat wrote: 5. Tom, Jane, and Sue each purchased a new house. The average (arithmetic mean) price of the three houses was$120,000. What was the median price of the three houses?
(1) The price of Tom’s house was $110,000. (2) The price of Jane’s house was$120,000.

kirakira wrote:
(B) it is

T + J + S = 120,000 x 3 = 360,000

(1) T = 110,000 => J + S = 250,000
=> Can not figure out the median => insuff

(2) J = 120,000 => T + S = 240,000
=> The median is 120,000 in all possible cases => suff

Hence, (B)

Many thanks for posting your reply. Answer is B ,but i am still not sure why B is suff. If T and S are 110,000 and 130,000 respectively, then also T+S= 240,000; Isn't it? Am i missing something here?
Manager
Joined: 17 May 2007
Posts: 72
Followers: 1

Kudos [?]: 20 [0], given: 0

isn't 'median' mean middle

so if it is

$110,000$120,000
$130,000 you still get$120,000 as the median. You're trying to find the middle of the three not the mean.

(am i off here?!?!?
Manager
Joined: 26 Aug 2006
Posts: 55
Followers: 1

Kudos [?]: 0 [0], given: 29

gowani wrote:
isn't 'median' mean middle

so if it is

$110,000$120,000
$130,000 you still get$120,000 as the median. You're trying to find the middle of the three not the mean.

(am i off here?!?!?

Gowani,
You are right.
Thanks,
Bharat
Display posts from previous: Sort by