If vmt <>(not equal) 0, is v^2m^3t^-4 > 0 ? 1. m : DS Archive
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# If vmt <>(not equal) 0, is v^2m^3t^-4 > 0 ? 1. m

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Senior Manager
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If vmt <>(not equal) 0, is v^2m^3t^-4 > 0 ? 1. m [#permalink]

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13 Oct 2006, 16:11
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If vmt <>(not equal) 0, is v^2m^3t^-4 > 0 ?

1. m > v^2
2. m> t^-4[/list]
Director
Joined: 23 Jun 2005
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13 Oct 2006, 17:49
D

For the question to be positive: v^2, m^3 and t^-4 = +ve

v^2 and t^-4 are always positive.

Statement 1:
m> v^2

So m positive. SUFF

Statement 2:

m> t^ -4

So, m positive. SUFF
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14 Oct 2006, 11:41
If vmt <>(not equal) 0, is v^2m^3t^-4 > 0 ?

1. m > v^2
2. m> t^-4

i WANT TO CLARIFY IS THE STEM

V RAISED TO THE POWER OF 2M RAISED TO THE POWER OF 3T RAISED TO THE POWER OF -4

OR WUT????????
Manager
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14 Oct 2006, 13:04
Assuming I am reading the question right, isn't v^2m^3t^-4 = v^ (-24mt)
So, don't we need to prove that 24mt itself is negative, so that -24mt will be positive.

1 shows that m > 0
2 also shows that m > 0.

But how do we know whether t <0 or >0?
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14 Oct 2006, 13:59
D

I) v^2 is +ve, therefore if m > v^2 then m is +ve, t^-4 +ve so:
+ve * +ve * +ve > 0

II) t^-4 +ve therefore m +ve
+ve * +ve * +ve > 0
14 Oct 2006, 13:59
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# If vmt <>(not equal) 0, is v^2m^3t^-4 > 0 ? 1. m

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