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Re: If w=(1+x*y/z^2)(x+y), x=z/2, and y=3z/4, what is the value [#permalink]

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08 Apr 2013, 05:57

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sandra1122 wrote:

If \(w=\frac{1+x\frac{y}{z^2}}{x+y}\), \(x=\frac{z}{2}\), and \(y=3\frac{z}{4}\),what is the value of w in terms of z?

A. 11z/10 B. 2z/5 C. 3z/10 D. 11z/10 E. 2z/5

I tried to solve the problem several times, but still didn't get the OA.

Notice that options A and D are the same, as well as options B and E, so there are typos in answer choices.

In order A to be the correct answer it should read 11/(10z).

Say z=4, then \(x=\frac{z}{2}=2\), and \(y=3\frac{z}{4}=3\).

So, in this case we'd have that x=2, y=3 and z=4. Plug these values in the fraction to get w=11/40. Now, plug z=4 into the answer choices to see which one yields 11/40. Only A fits (assuming that there IS a typo and A actually must be 11/(10z)).

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