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Re: If w and Z are positive is W/Z<1 ? 1 w<2 2 Z<4 [#permalink]
OA is A ..
Can anyone tell why it is A?

Even I arrived at E.
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Re: If w and Z are positive is W/Z<1 ? 1 w<2 2 Z<4 [#permalink]
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SUNGMAT710 wrote:
If w and Z are positive is W/Z<1 ?

1 w<2
2 Z<4

OA is A ..
Can anyone tell why it is A?

Even I arrived at E.


The correct answer is E, not A. Consider w=1 and z=2 for an YES answer and w=1 and z=1/2 for a NO answer.
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Re: If w and z are positive is w/z < 1 ? [#permalink]
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Hi Bunuel,
I agree with the answer. However, I noticed a typo in your explanation. "As given that z is positive we can safely multiply inequality by it and we'll get w>z. So the question becomes: is w>z?" When you multiply W/Z<1 by Z , you will get W<Z. Isn't that correct?
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Re: If w and z are positive is w/z < 1 ? [#permalink]
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rumehta wrote:
Hi Bunuel,
I agree with the answer. However, I noticed a typo in your explanation. "As given that z is positive we can safely multiply inequality by it and we'll get w>z. So the question becomes: is w>z?" When you multiply W/Z<1 by Z , you will get W<Z. Isn't that correct?


Typo edited. Thank you.
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Re: If w and z are positive is w/z < 1 ? [#permalink]
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xmagedo wrote:
If w and z are positive is w/z < 1 ?

(1) w < 2
(2) z < 4


Lets combine straight away:

w = 1 and z = 3 and w/z is less than 1

w = 1 and z = 0.5 and w/z is greater than 1

Hence E
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Re: If w and z are positive is w/z < 1 ? [#permalink]
Bunuel wrote:
xmagedo wrote:
If w and Z are positive is W/Z<1 ?

1 w<2
2 Z<4


As given that \(z\) is positive we can safely multiply inequality \(\frac{w}{z}<1\) by it and we'll get \(w<z\). So the question becomes: is \(w<z\)?

(1) \(w<2\). No info about \(z\), not sufficient.
(2) \(z<4\). No info about \(w\), not sufficient.

(1)+(2) Still not sufficient, as \(w\) from the range \(0<w<2\) may or may not be more less than \(z\) from the range \(0<z<4\).

Answer: E.


Hello Bunuel,

If statement 1 would be "w<z" instead of "w<2" then also answer would be E?
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Re: If w and z are positive is w/z < 1 ? [#permalink]
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anairamitch1804 wrote:
Bunuel wrote:
xmagedo wrote:
If w and Z are positive is W/Z<1 ?

1 w<2
2 Z<4


As given that \(z\) is positive we can safely multiply inequality \(\frac{w}{z}<1\) by it and we'll get \(w<z\). So the question becomes: is \(w<z\)?

(1) \(w<2\). No info about \(z\), not sufficient.
(2) \(z<4\). No info about \(w\), not sufficient.

(1)+(2) Still not sufficient, as \(w\) from the range \(0<w<2\) may or may not be more less than \(z\) from the range \(0<z<4\).

Answer: E.


Hello Bunuel,

If statement 1 would be "w<z" instead of "w<2" then also answer would be E?


In this case the answer would be A because the question asks exactly whether w < z.
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Re: If w and z are positive is w/z < 1 ? [#permalink]
w/z < 1 => w<z (we can move the variable around inequality since we know both are positive)
Question asks - is w < z ?

Clearly both statement are insufficient.
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Re: If w and z are positive is w/z < 1 ? [#permalink]
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