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If x<0 and 0<(x/y)+1<1, which of the following must

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SVP
SVP
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Joined: 24 Aug 2006
Posts: 2134
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Kudos [?]: 98 [0], given: 0

If x<0 and 0<(x/y)+1<1, which of the following must [#permalink] New post 11 Nov 2006, 20:11
If x<0 and 0<(x/y)+1<1, which of the following must be true?

I. y>0

II. (x/y)>-1

III. (1/x) + (1/y) < 0

I only
I and II only
I and III only
II and III only
I, II and III
Manager
Manager
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Joined: 03 Nov 2006
Posts: 161
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Kudos [?]: 3 [0], given: 0

 [#permalink] New post 11 Nov 2006, 22:14
I'm going for E here.
Current Student
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Joined: 29 Jan 2005
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Kudos [?]: 180 [0], given: 0

 [#permalink] New post 12 Nov 2006, 05:35
x must be less than y for the stem to hold. (E) wins here.
SVP
SVP
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Kudos [?]: 118 [0], given: 39

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 [#permalink] New post 12 Nov 2006, 05:36
If x<0 and 0<(x/y)+1<1, which of the following must be true?

I. y>0

II. (x/y)>-1

III. (1/x) + (1/y) < 0

I only I and II only I and III only II and III only I , II and III.

X is -ve

-1< x/y< 0 therfore x/y is -ve fraction

x is -ve thus y is +ve

the three are valid must
VP
VP
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Posts: 1384
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Kudos [?]: 20 [0], given: 0

 [#permalink] New post 12 Nov 2006, 11:34
If x<0 and 0<(x/y)+1<1, which of the following must be true?

I. y>0

II. (x/y)>-1

III. (1/x) + (1/y) < 0


From the stem if (x/y)+1 is between 0 and 1 then it is a fraction between 0 and 1.

Since x<0 then y>0 so that the (x/y)+1 is a value between 0 and 1.

So 1) and 2 are true

(1/x) + (1/y) < 0 means x+y <0 which is also correct

So E is the answer
  [#permalink] 12 Nov 2006, 11:34
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If x<0 and 0<(x/y)+1<1, which of the following must

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