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If x≠0 and x=sq rt (4xy-4y2), then, in terms of y,

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If x≠0 and x=sq rt (4xy-4y2), then, in terms of y,  [#permalink] New post 09 Feb 2004, 12:17
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17. If x≠0 and x=sq rt (4xy-4y2), then, in terms of y,
(A) 2y
(B) y
(C) y/2
(D) -4y2/1-2y
(E) тАУ2y
Manager
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 [#permalink] New post 09 Feb 2004, 12:27
Can you elobrate on that..I tried to square it too..But didnt get the desired results.

Thanks
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Attain Moksha

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 [#permalink] New post 09 Feb 2004, 12:30
X^2 = 4XY - 4Y^2
X^2 - 4XY + 4Y^2 = 0
(X - 2Y)^2 = 0

or

X - 2Y = 0

X = 2Y

Hope, this helps!
Manager
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Joined: 07 Jul 2003
Posts: 60
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 [#permalink] New post 09 Feb 2004, 12:41
Thanks, Dont believe I couldnt solve that one..

Thanks again...
  [#permalink] 09 Feb 2004, 12:41
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If x≠0 and x=sq rt (4xy-4y2), then, in terms of y,

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