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Re: If x#0 and x/|x|<x, which of the following must be true? [#permalink]
04 Dec 2012, 04:03

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Marcab wrote:

If x\neq{0} and \frac{x}{|x|}<x, which of the following must be true?

(A) x>1

(B) x>-1

(C) |x|<1

(D) |x|>1

(E) -1<x<0

Explanations required for this one. Not convinced at all with the OA.

My range is -1<x<0 and x>1.

Notice that we are asked to find which of the options MUST be true, not COULD be true.

Let's see what ranges does \frac{x}{|x|}< x give for x. Two cases:

If x<0 then |x|=-x, hence in this case we would have: \frac{x}{-x}<x --> -1<x. But remember that we consider the range x<0, so -1<x<0;

If x>0 then |x|=x, hence in this case we would have: \frac{x}{x}<x --> 1<x.

So, \frac{x}{|x|}< x means that -1<x<0 or x>1.

Only option which is ALWAYS true is B. ANY x from the range -1<x<0 or x>1 will definitely be more the -1.

Answer: B.

As for other options:

A. x>1. Not necessarily true since x could be -0.5; C. |x|<1 --> -1<x<1. Not necessarily true since x could be 2; D. |x|>1 --> x<-1 or x>1. Not necessarily true since x could be -0.5; E. -1<x<0. Not necessarily true since x could be 2.

Re: If x#0 and x/|x|<x, which of the following must be true? [#permalink]
04 Dec 2012, 04:14

Expert's post

If you choose 0.9, then B fails. I just reviewed m09 q22 on the forum. You have changed the answer choices in that thread but not yet on GC CAT. _________________

Re: If x#0 and x/|x|<x, which of the following must be true? [#permalink]
04 Dec 2012, 04:36

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Marcab wrote:

That's what I am saying. Since x cannot take this value then how can B be answer. How can x>-1 when 0<x<1 is not accepted?

Consider following: If x=5, then which of the following must be true about x: A. x=3 B. x^2=10 C. x<4 D. |x|=1 E. x>-10

Answer is E (x>-10), because as x=5 then it's more than -10.

Or: If -1<x<10, then which of the following must be true about x: A. x=3 B. x^2=10 C. x<4 D. |x|=1 E. x<120

Again answer is E, because ANY x from -1<x<10 will be less than 120 so it's always true about the number from this range to say that it's less than 120.

The same with original question:

If -1<x<0 or x>1, then which of the following must be true about x: A. x>1 B. x>-1 C. |x|<1 D. |x|>1 E. -1<x<0

As -1<x<0 or x>1 then ANY x from these ranges would satisfy x>-1. So B is always true.

x could be for example -1/2, -3/4, or 10 but no matter what x actually is, it's IN ANY CASE more than -1. So we can say about x that it's more than -1.

Re: If x#0 and x/|x|<x, which of the following must be true? [#permalink]
04 Dec 2012, 18:48

\frac{x}{|x|}<x

Test the values for x.

(1) x = 0 ==> No! Since it is given that x is not 0 (2) x = -1 ==> -1 < -1 ==> No! (3) x = 1 ==> 1 < 1 ==> No! (4) x = -2 ==> -1 < -2 ==> No! (5) x = \frac{-1}{4} ==> -1 < \frac{-1}{4} ===> Yes! (5) x = 2 ==> 1 < 2 ==> Yes!

Our range: -1 < x < 0 or x > 1

What must always be true in that range? x > -1 always

Re: If x#0 and x/|x|<x, which of the following must be true? [#permalink]
08 Dec 2012, 18:05

Marcab wrote:

Hey thanks. Its crystal clear now.

Yes - same here.

The word in that explanation that helped me the most is "satify". I think the difficulty of this question is good. The learning moment is also exactley what I needed. The language is what confused me on the first attempt. I think it would be understood by more people if the question had the english rephrased to: "... which of the following statements can be satisfied by all possible values of x".

Having said that, I learnt a lot about absolute values on the number plane trying to get my head around this explanation, so maybe it's helping us learn in the best way possible

Re: If x#0 and x/|x|<x, which of the following must be true? [#permalink]
16 Dec 2012, 20:04

But your dividing my the same number x on both sides, whether its positive or negative, implying both sides will simultaneously be negative together or positive together which doesnt change the sign.

Re: If x#0 and x/|x|<x, which of the following must be true? [#permalink]
16 Dec 2012, 22:18

1

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Expert's post

eaakbari wrote:

Appreciate if someone could point out where I am going wrong here.

x / |x| < x

Since x is non zero, dividing by x on both sides

1 / |x| < 1

Taking reciprocal,

|x| > 1

Then I just jumped into Choice D. Didn't even look at the others.

Await your valued views.

Never multiply (or reduce) an inequality by variable (or by an expression with variable) if you don't know its sign.

So you cannot divide both parts of inequality x / |x| < x by x as you don't know the sign of this unknown: if x>0 you should write 1/|x|<1 BUT if x<0 you should write 1/|x|>1.

Re: If x#0 and x/|x|<x, which of the following must be true? [#permalink]
17 Dec 2012, 23:48

Ans:

we take two cases as we see there is a modulus sign. The equation becomes x(1-|x|)<0 and then after solving for both cases we get x to be always greater than -1, so the answer is (B). _________________

Re: If x#0 and x/|x|<x, which of the following must be true? [#permalink]
12 Feb 2013, 19:37

1

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Expert's post

Quote:

If x\neq{0} and \frac{x}{|x|}<x, which of the following must be true?

(A) x>1

(B) x>-1

(C) |x|<1

(D) |x|>1

(E) -1<x<0

Hi Karishma Can you pls help me with the answer to the above link. I was able to solve the inequality My answer after solving inequality is -1<x<0 or x>1 So how can be the answer not E The point of elimination for option e in the official explanation is as given below:-How can x be 2 when the range is less than 0...... E. −1<x<0. Not necessarily true since x could be 2.

A 'must be true' question! They are absolutely straight forward if you get the fundamental but they can drive you crazy if you don't.

"My answer after solving inequality is -1<x<0 or x>1" Perfect. That is the range of x for which the inequality works. So tell me, what values can x take? -1/2, -1/3, -2/3, 1.4, 2, 500, 123498 etc... Now the question is "which of the following must be true?"

(A) x>1 Are all these values greater than 1? No.

(B) x>-1 Are all these values greater than -1? Yes. The answer. Note that you dont have to establish that all value greater than -1 should work for the inequality. You only have to establish that all values which work for the inequality must satisfy this condition.

(C) |x|<1 Not true for all values of x.

(D) |x|>1 Not true for all values of x.

(E) -1<x<0 Not true for all values of x. x can take values 1.4, 2, 500 etc

Re: GMAT quant DS question from GMAT club tests [#permalink]
01 May 2013, 20:28

Expert's post

rongali wrote:

If x≠0 and x / |x| < x, which of the following must be true

A) x>1 B) x>−1 c) |x|<1 D) |x|>1 E) −1<x<0

why is B an answer, as the equation wont hold true for values between 0<x<1

Mark as a guessHide Answer

I think the answer is absolutely correct. Firstly the question asks for a "MUST be true" option. Both the ranges for x, as rightly calculated above are : x>1 OR -1<x<0. However, none of the options subscribe to MUST be true type.It is so because x could be 2 OR x could be -0.5 However, the option B, where x>-1 will always be true, irrespective of the two ranges. Any value lying in the range -1<x<0 IS always in tandem with x>-1 AND any value for x>1 WILL also have x>-1. _________________

Re: GMAT quant DS question from GMAT club tests [#permalink]
01 May 2013, 20:38

Expert's post

doe007 wrote:

When x = 1/2, x is GT -1, but x / |x| is NOT < x Thus we cannot say that x / |x| < x for all x > -1. Option B is wrong.

We are not saying that x / |x| < x for all x > -1. That defies the whole purpose of breaking down the given inequality into 2 ranges. All we are saying is that for the 2 given ranges, the value of x MUST BE x>-1. You are taking the value of x=0.5, which in the first place is invalid for the given problem. _________________

Re: GMAT quant DS question from GMAT club tests [#permalink]
01 May 2013, 20:52

Expert's post

doe007 wrote:

vinaymimani wrote:

doe007 wrote:

When x = 1/2, x is GT -1, but x / |x| is NOT < x Thus we cannot say that x / |x| < x for all x > -1. Option B is wrong.

We are not saying that x / |x| < x for all x > -1. That defies the whole purpose of breaking down the given inequality into 2 ranges. All we are saying is that for the 2 given ranges, the value of x MUST BE x>-1. You are taking the value of x=0.5, which in the first place is invalid for the given problem.

The question is asking to find the rage in which all values of would satisfy the inequality x / |x| < x. As the example shown, definitely some values in the range x > -1 do not satisfy the inequality. Hence, we CANNOT say that x > -1 must be true to satisfy x / |x| < x.

The question at NO point of time has asked "to find the rage in which all values of x would satisfy the inequality x / |x| < x", It just says which of the following MUST be TRUE. You don't assume that the given options encompass all the valid ranges. You find the valid ranges, then look for a common thread which binds them together and MUST BE TRUE, irrespective of the range(s). _________________

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