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1) x has to be a fraction => regardless of the sign x is less than 1 => suff
1) |x|x<1 => x can be fraction or x is neg; in both cases the stem is satisfied but |x| is > 1 or <1 or = 1 => insuff

1) x has to be a fraction => regardless of the sign x is less than 1 => suff 1) |x|x<1 => x can be fraction or x is neg; in both cases the stem is satisfied but |x| is > 1 or <1 or = 1 => insuff

u can't multiply the inequality with a the variable, it changes the inequality...try x = -1/2 in statement 2 as see if that satisifies

1) x has to be a fraction => regardless of the sign x is less than 1 => suff 1) |x|x<1 => x can be fraction or x is neg; in both cases the stem is satisfied but |x| is > 1 or <1 or = 1 => insuff

u can't multiply the inequality with a the variable, it changes the inequality...try x = -1/2 in statement 2 as see if that satisifies

Ans shud be "D".

...because i dont know whether the variable is neg or pos ! thx baner...

the argument doesnt mention <= or >= it only says < or >

one more for D
in statement 1 only the Sq of a really small no. is gonna be <1 (on both sides of 0)
statement 2: if it were negative there is no way this holds, as a lxl cannot be < (any negative number)
now comes the question ...does this make statement 2 insufficient or sufficient.
I THINK it makes it sufficient cause by math rules it implies that x cannot be negative
therefore we can only look at the possibility of X being positive.
from that angle it is sufficient.