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If x?0, is |x| <1? (1) x^2<1 (2) |x| < 1/x

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VP
Joined: 25 Nov 2004
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If x?0, is |x| <1? (1) x^2<1 (2) |x| < 1/x [#permalink]  08 Mar 2005, 23:20
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Question Stats:

100% (01:58) correct 0% (00:00) wrong based on 1 sessions
If x≠0, is |x| <1?
(1) x^2<1
(2) |x| < 1/x
Intern
Joined: 29 Oct 2003
Posts: 9
Location: Netherlands
Followers: 0

Kudos [?]: 1 [0], given: 0

I will go with D!

i) is sufficient

ii) is also sufficient as it only narrow down the value of X to a positive number.
VP
Joined: 30 Sep 2004
Posts: 1488
Location: Germany
Followers: 4

Kudos [?]: 105 [0], given: 0

A)

1) x has to be a fraction => regardless of the sign x is less than 1 => suff
1) |x|x<1 => x can be fraction or x is neg; in both cases the stem is satisfied but |x| is > 1 or <1 or = 1 => insuff
VP
Joined: 18 Nov 2004
Posts: 1441
Followers: 2

Kudos [?]: 22 [0], given: 0

christoph wrote:
A)

1) x has to be a fraction => regardless of the sign x is less than 1 => suff
1) |x|x<1 => x can be fraction or x is neg; in both cases the stem is satisfied but |x| is > 1 or <1 or = 1 => insuff

u can't multiply the inequality with a the variable, it changes the inequality...try x = -1/2 in statement 2 as see if that satisifies

Ans shud be "D".
Director
Joined: 21 Sep 2004
Posts: 612
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Kudos [?]: 9 [0], given: 0

-1<x<1

and x not equal to 0
there fore it has to be a fraction..
and has to be <1..

a sufficient
b sufficient..
VP
Joined: 30 Sep 2004
Posts: 1488
Location: Germany
Followers: 4

Kudos [?]: 105 [0], given: 0

banerjeea_98 wrote:
christoph wrote:
A)

1) x has to be a fraction => regardless of the sign x is less than 1 => suff
1) |x|x<1 => x can be fraction or x is neg; in both cases the stem is satisfied but |x| is > 1 or <1 or = 1 => insuff

u can't multiply the inequality with a the variable, it changes the inequality...try x = -1/2 in statement 2 as see if that satisifies

Ans shud be "D".

...because i dont know whether the variable is neg or pos ! thx baner...
Manager
Joined: 15 Feb 2005
Posts: 246
Location: Rockville
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Kudos [?]: 6 [0], given: 0

the argument doesnt mention <= or >= it only says < or >

one more for D
in statement 1 only the Sq of a really small no. is gonna be <1 (on both sides of 0)
statement 2: if it were negative there is no way this holds, as a lxl cannot be < (any negative number)
now comes the question ...does this make statement 2 insufficient or sufficient.
I THINK it makes it sufficient cause by math rules it implies that x cannot be negative
therefore we can only look at the possibility of X being positive.
from that angle it is sufficient.
SVP
Joined: 03 Jan 2005
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http://www.gmatclub.com/phpbb/viewtopic ... 9780#89780
VP
Joined: 25 Nov 2004
Posts: 1494
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Kudos [?]: 40 [0], given: 0

Gr8. I agree with you all.
Thanx guys.
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5068
Location: Singapore
Followers: 23

Kudos [?]: 194 [0], given: 0

From 1.

-1<x<1
So (1) is sufficient since we can answer yes/no to |x| < 1

From 2.

Positive x case:

x < 1/x
x^2<1 (sufficient)

Negative x case:
x < -1/-x
x < 1/x
x^2 < 1 (sufficient)

Ans: D
Manager
Joined: 01 Jan 2005
Posts: 167
Location: NJ
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Kudos [?]: 0 [0], given: 0

From each of the statements x is between 0 and 1. Thus , yes |x|<1.

D.
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