Find all School-related info fast with the new School-Specific MBA Forum

It is currently 30 Aug 2016, 03:01
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If x 0, is x^2/IxI < 1? (1) x < 1 (2) x > 1

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
VP
VP
avatar
Joined: 22 Nov 2007
Posts: 1092
Followers: 9

Kudos [?]: 426 [0], given: 0

If x 0, is x^2/IxI < 1? (1) x < 1 (2) x > 1 [#permalink]

Show Tags

New post 19 Jan 2008, 06:57
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x ≠ 0, is x^2/IxI < 1?
(1) x < 1
(2) x > −1
Expert Post
CEO
CEO
User avatar
Joined: 17 Nov 2007
Posts: 3589
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 502

Kudos [?]: 3075 [0], given: 360

Re: abs value [#permalink]

Show Tags

New post 19 Jan 2008, 07:59
C

\(x^2/|x| < 1 \text{ }\to\text{ }|x| < 1\text{ }\to\text{ } x e (-1,1)\)

1. \(x e (-\infty,1)\) insuff.

2. \(x e (-1,\infty)\) insuff.

1&2. \(x e (-1,1)\) suff.
_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

Manager
Manager
User avatar
Joined: 01 Jan 2008
Posts: 227
Schools: Booth, Stern, Haas
Followers: 1

Kudos [?]: 53 [0], given: 2

Re: abs value [#permalink]

Show Tags

New post 19 Jan 2008, 08:59
walker wrote:
C

\(x^2/|x| < 1 \text{ }\to\text{ }|x| < 1\text{ }\to\text{ } x e (-1,1)\)

1. \(x e (-\infty,1)\) insuff.

2. \(x e (-1,\infty)\) insuff.

1&2. \(x e (-1,1)\) suff.


how did you get rid of x^2?
Expert Post
CEO
CEO
User avatar
Joined: 17 Nov 2007
Posts: 3589
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 502

Kudos [?]: 3075 [0], given: 360

Re: abs value [#permalink]

Show Tags

New post 19 Jan 2008, 09:06
\(\frac{x^2}{|x|}=\frac{|x|^2}{|x|}=|x|\)
_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

SVP
SVP
avatar
Joined: 28 Dec 2005
Posts: 1575
Followers: 3

Kudos [?]: 130 [0], given: 2

Re: abs value [#permalink]

Show Tags

New post 27 Jan 2008, 16:12
from stem, can conclude that inequality only holds if -1<x<1

stat 1 says x<1. try something like x=-2 and youll see it doesnt work. insuff

stat 2 says x>-1. try something like x=2 and youll see it doesnt work, but for something like x=-1/2, it does. insuff.

together, we know -1<x<1. sufficient.
Director
Director
avatar
Joined: 01 May 2007
Posts: 792
Followers: 1

Kudos [?]: 248 [0], given: 0

Re: abs value [#permalink]

Show Tags

New post 27 Jan 2008, 17:01
Also can solve by rephrasing the question...

Rephrase Is...

(x^2/x^1) < 1 which calculated to x < 1

and since it is abs value...

(x^2/-x^1) < 1 which calculated to -x < 1, rearrange to x > -1

So A gives us x < 1
and B gives us x > -1

So the answer is C
Re: abs value   [#permalink] 27 Jan 2008, 17:01
Display posts from previous: Sort by

If x 0, is x^2/IxI < 1? (1) x < 1 (2) x > 1

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.