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# If x = 0. rstu, where r, s, t, and u each represent a

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Director
Joined: 12 Oct 2008
Posts: 557
Followers: 2

Kudos [?]: 147 [0], given: 2

If x = 0. rstu, where r, s, t, and u each represent a [#permalink]  10 May 2009, 14:59
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If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x?
(1) r = 3s = 2t = 6u
(2) The product of r and u is equal to the product of s and t.
SVP
Joined: 07 Nov 2007
Posts: 1824
Location: New York
Followers: 29

Kudos [?]: 561 [0], given: 5

Re: DS: X=0 [#permalink]  10 May 2009, 15:17
If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x?
(1) r = 3s = 2t = 6u
(2) The product of r and u is equal to the product of s and t.

r,s,t,u VALUES must be in the range.. 1 to 9

(i)
r=6u... u must be 1 becuase if u=2 r value is >9

u=1 r=6 s =2 2=3

sufficient
(2)

ru=st

r=4 and u=2 s=1 t=8
r=2 and u=8 s=8 t=1

multiple solutions.

not sufficient

A
_________________

Smiling wins more friends than frowning

Director
Joined: 12 Oct 2008
Posts: 557
Followers: 2

Kudos [?]: 147 [0], given: 2

Re: DS: X=0 [#permalink]  10 May 2009, 15:36
How A? it is not given what is the place of r,s,t and u??????

It can be 0.1236, 0.2316 so on...
x2suresh wrote:
If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x?
(1) r = 3s = 2t = 6u
(2) The product of r and u is equal to the product of s and t.

r,s,t,u VALUES must be in the range.. 1 to 9

(i)
r=6u... u must be 1 becuase if u=2 r value is >9

u=1 r=6 s =2 2=3

sufficient
(2)

ru=st

r=4 and u=2 s=1 t=8
r=2 and u=8 s=8 t=1

multiple solutions.

not sufficient

A
SVP
Joined: 07 Nov 2007
Posts: 1824
Location: New York
Followers: 29

Kudos [?]: 561 [0], given: 5

Re: DS: X=0 [#permalink]  10 May 2009, 19:11
How A? it is not given what is the place of r,s,t and u??????

It can be 0.1236, 0.2316 so on...
x2suresh wrote:
If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x?
(1) r = 3s = 2t = 6u
(2) The product of r and u is equal to the product of s and t.

r,s,t,u VALUES must be in the range.. 1 to 9

(i)
r=6u... u must be 1 becuase if u=2 r value is >9

u=1 r=6 s =2 t=3

sufficient
(2)

ru=st

r=4 and u=2 s=1 t=8
r=2 and u=8 s=8 t=1

multiple solutions.

not sufficient

A

0.1236 ,0.2316
are not possible solutions

they don't satisfy the following equations.
r = 3s = 2t = 6u

only one solution possible... and that is 0.6231

Let me know any solution other than "0.6231" and satisfies above equation.
_________________

Smiling wins more friends than frowning

Senior Manager
Joined: 08 Jan 2009
Posts: 329
Followers: 2

Kudos [?]: 91 [0], given: 5

Re: DS: X=0 [#permalink]  10 May 2009, 19:13
Same working . Got A.

It is given x = 0.rstu so x can be only equal to x =.6231.
Director
Joined: 12 Oct 2008
Posts: 557
Followers: 2

Kudos [?]: 147 [0], given: 2

Re: DS: X=0 [#permalink]  12 May 2009, 15:17
thx Suresh....OA A
Director
Joined: 23 May 2008
Posts: 839
Followers: 3

Kudos [?]: 39 [0], given: 0

Re: DS: X=0 [#permalink]  12 May 2009, 21:46
got A

only possible soln is let r=6

x=0.6231
Re: DS: X=0   [#permalink] 12 May 2009, 21:46
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