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If x = 0. rstu, where r, s, t, and u each represent a [#permalink]

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If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x? (1) r = 3s = 2t = 6u (2) The product of r and u is equal to the product of s and t.

If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x? (1) r = 3s = 2t = 6u (2) The product of r and u is equal to the product of s and t.

r,s,t,u VALUES must be in the range.. 1 to 9

(i) r=6u... u must be 1 becuase if u=2 r value is >9

u=1 r=6 s =2 2=3

sufficient (2)

ru=st

r=4 and u=2 s=1 t=8 r=2 and u=8 s=8 t=1

multiple solutions.

not sufficient

A
_________________

Your attitude determines your altitude Smiling wins more friends than frowning

How A? it is not given what is the place of r,s,t and u??????

It can be 0.1236, 0.2316 so on...

x2suresh wrote:

reply2spg wrote:

If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x? (1) r = 3s = 2t = 6u (2) The product of r and u is equal to the product of s and t.

r,s,t,u VALUES must be in the range.. 1 to 9

(i) r=6u... u must be 1 becuase if u=2 r value is >9

How A? it is not given what is the place of r,s,t and u??????

It can be 0.1236, 0.2316 so on...

x2suresh wrote:

reply2spg wrote:

If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x? (1) r = 3s = 2t = 6u (2) The product of r and u is equal to the product of s and t.

r,s,t,u VALUES must be in the range.. 1 to 9

(i) r=6u... u must be 1 becuase if u=2 r value is >9

u=1 r=6 s =2 t=3

sufficient (2)

ru=st

r=4 and u=2 s=1 t=8 r=2 and u=8 s=8 t=1

multiple solutions.

not sufficient

A

0.1236 ,0.2316 are not possible solutions

they don't satisfy the following equations. r = 3s = 2t = 6u

only one solution possible... and that is 0.6231

Let me know any solution other than "0.6231" and satisfies above equation.
_________________

Your attitude determines your altitude Smiling wins more friends than frowning