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If x = 0. rstu, where r, s, t, and u each represent a [#permalink]
10 May 2009, 14:59
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If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x? (1) r = 3s = 2t = 6u (2) The product of r and u is equal to the product of s and t.
If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x? (1) r = 3s = 2t = 6u (2) The product of r and u is equal to the product of s and t.
r,s,t,u VALUES must be in the range.. 1 to 9
(i) r=6u... u must be 1 becuase if u=2 r value is >9
u=1 r=6 s =2 2=3
sufficient (2)
ru=st
r=4 and u=2 s=1 t=8 r=2 and u=8 s=8 t=1
multiple solutions.
not sufficient
A _________________
Your attitude determines your altitude Smiling wins more friends than frowning
How A? it is not given what is the place of r,s,t and u??????
It can be 0.1236, 0.2316 so on...
x2suresh wrote:
reply2spg wrote:
If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x? (1) r = 3s = 2t = 6u (2) The product of r and u is equal to the product of s and t.
r,s,t,u VALUES must be in the range.. 1 to 9
(i) r=6u... u must be 1 becuase if u=2 r value is >9
How A? it is not given what is the place of r,s,t and u??????
It can be 0.1236, 0.2316 so on...
x2suresh wrote:
reply2spg wrote:
If x = 0. rstu, where r, s, t, and u each represent a nonzero digit of x, what is the value of x? (1) r = 3s = 2t = 6u (2) The product of r and u is equal to the product of s and t.
r,s,t,u VALUES must be in the range.. 1 to 9
(i) r=6u... u must be 1 becuase if u=2 r value is >9
u=1 r=6 s =2 t=3
sufficient (2)
ru=st
r=4 and u=2 s=1 t=8 r=2 and u=8 s=8 t=1
multiple solutions.
not sufficient
A
0.1236 ,0.2316 are not possible solutions
they don't satisfy the following equations. r = 3s = 2t = 6u
only one solution possible... and that is 0.6231
Let me know any solution other than "0.6231" and satisfies above equation. _________________
Your attitude determines your altitude Smiling wins more friends than frowning