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# If x != 0, then sqrt(x^2)/x = i) -1 ii) 0 iii) 1 iv) x v)

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Manager
Joined: 04 Dec 2005
Posts: 79
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Kudos [?]: 2 [0], given: 0

If x != 0, then sqrt(x^2)/x = i) -1 ii) 0 iii) 1 iv) x v) [#permalink]  07 Oct 2006, 20:20
If x != 0, then sqrt(x^2)/x =

i) -1
ii) 0
iii) 1
iv) x
v) |x|/x

I selected iii) thinking that in GMAT world sqrt(x) is always positive. Please let me know the answer
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Manager
Joined: 01 Oct 2006
Posts: 242
Followers: 1

Kudos [?]: 5 [0], given: 0

Re: GMAT Prep question [#permalink]  07 Oct 2006, 21:54
sqrt (x^2)/x = +x/x or -x/x. Therefore answer should be v
Senior Manager
Joined: 30 Aug 2006
Posts: 374
Followers: 3

Kudos [?]: 20 [0], given: 0

[#permalink]  08 Oct 2006, 13:10
V) |x| / x

you destroy the sign by taking the square root of a square, therefore it is the same as saying |x|,

e.g. x^2 = 4 x could be -2 or 2
sqrt 4 = 2 we have lost the -2
Director
Joined: 23 Jun 2005
Posts: 847
GMAT 1: 740 Q48 V42
Followers: 5

Kudos [?]: 31 [0], given: 1

Re: GMAT Prep question [#permalink]  08 Oct 2006, 19:09
withme wrote:
If x != 0, then sqrt(x^2)/x =

i) -1
ii) 0
iii) 1
iv) x
v) |x|/x

I selected iii) thinking that in GMAT world sqrt(x) is always positive. Please let me know the answer

C)1

Seems straight forward, unless I'm missing something very basic.
Director
Joined: 23 Jun 2005
Posts: 847
GMAT 1: 740 Q48 V42
Followers: 5

Kudos [?]: 31 [0], given: 1

[#permalink]  08 Oct 2006, 19:11
Guys,
Since the question specifically mentions sqrt(x^2), the root can be only x, right? For example, sqrt (4^2) can only be 4 not, +/-4.
[#permalink] 08 Oct 2006, 19:11
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# If x != 0, then sqrt(x^2)/x = i) -1 ii) 0 iii) 1 iv) x v)

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