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If x != 0, then sqrt(x^2)/x = i) -1 ii) 0 iii) 1 iv) x v)

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Manager
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If x != 0, then sqrt(x^2)/x = i) -1 ii) 0 iii) 1 iv) x v) [#permalink] New post 07 Oct 2006, 20:20
If x != 0, then sqrt(x^2)/x =

i) -1
ii) 0
iii) 1
iv) x
v) |x|/x

I selected iii) thinking that in GMAT world sqrt(x) is always positive. Please let me know the answer
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Manager
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Re: GMAT Prep question [#permalink] New post 07 Oct 2006, 21:54
sqrt (x^2)/x = +x/x or -x/x. Therefore answer should be v
Senior Manager
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 [#permalink] New post 08 Oct 2006, 13:10
V) |x| / x

you destroy the sign by taking the square root of a square, therefore it is the same as saying |x|,

e.g. x^2 = 4 x could be -2 or 2
sqrt 4 = 2 we have lost the -2
Director
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Re: GMAT Prep question [#permalink] New post 08 Oct 2006, 19:09
withme wrote:
If x != 0, then sqrt(x^2)/x =

i) -1
ii) 0
iii) 1
iv) x
v) |x|/x

I selected iii) thinking that in GMAT world sqrt(x) is always positive. Please let me know the answer


C)1

Seems straight forward, unless I'm missing something very basic.
Director
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Joined: 23 Jun 2005
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GMAT 1: 740 Q48 V42
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Kudos [?]: 23 [0], given: 1

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 [#permalink] New post 08 Oct 2006, 19:11
Guys,
Since the question specifically mentions sqrt(x^2), the root can be only x, right? For example, sqrt (4^2) can only be 4 not, +/-4.
  [#permalink] 08 Oct 2006, 19:11
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If x != 0, then sqrt(x^2)/x = i) -1 ii) 0 iii) 1 iv) x v)

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