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# If x<0, then sqrt (-x |x|) = ? 1: -x 2: -1 3: 1 4: x 5:

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Manager
Joined: 07 Feb 2007
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If x<0, then sqrt (-x |x|) = ? 1: -x 2: -1 3: 1 4: x 5: [#permalink]  29 Jul 2007, 13:44
If x<0, then sqrt (-x |x|) = ?

1: -x
2: -1
3: 1
4: x
5: sqrt (x)
Manager
Joined: 27 May 2007
Posts: 128
Followers: 1

Kudos [?]: 4 [0], given: 0

Re: Sqrt Mod X [#permalink]  29 Jul 2007, 13:54
abhi_ferrari wrote:
If x<0, then sqrt (-x |x|) = ?

1: -x
2: -1
3: 1
4: x
5: sqrt (x)

I get -x. (the opposite of x, in this case a positive number, since x is negative)

Sqrt(-x lxl) If x is <0, -x is positive. so -x and lxl are equal, together they equal -(the opposite of)x^2. Since the square root is positive, it will be the opposite of the negative number x, or -x.
Manager
Joined: 07 Feb 2007
Posts: 54
Followers: 1

Kudos [?]: 0 [0], given: 0

Re: Sqrt Mod X [#permalink]  29 Jul 2007, 14:22
Robin in NC wrote:
abhi_ferrari wrote:
If x<0, then sqrt (-x |x|) = ?

1: -x
2: -1
3: 1
4: x
5: sqrt (x)

I get -x. (the opposite of x, in this case a positive number, since x is negative)

Sqrt(-x lxl) If x is <0, -x is positive. so -x and lxl are equal, together they equal -(the opposite of)x^2. Since the square root is positive, it will be the opposite of the negative number x, or -x.

Thanks, Robin. OA is infact A. I tried to put in value of x (say -2) and got 2 as the answer (so got x instead of -x). What am I doing wrong?
Manager
Joined: 27 May 2007
Posts: 128
Followers: 1

Kudos [?]: 4 [0], given: 0

Re: Sqrt Mod X [#permalink]  29 Jul 2007, 14:33
abhi_ferrari wrote:
Robin in NC wrote:
abhi_ferrari wrote:
If x<0, then sqrt (-x |x|) = ?

1: -x
2: -1
3: 1
4: x
5: sqrt (x)

I get -x. (the opposite of x, in this case a positive number, since x is negative)

Sqrt(-x lxl) If x is <0, -x is positive. so -x and lxl are equal, together they equal -(the opposite of)x^2. Since the square root is positive, it will be the opposite of the negative number x, or -x.

Thanks, Robin. OA is infact A. I tried to put in value of x (say -2) and got 2 as the answer (so got x instead of -x). What am I doing wrong?

An answer of 2 would correspond to -x. Remember, x is a negative number, so -x is a positive number (the opposite of x) If x=-2, -x=2.
Manager
Joined: 07 Feb 2007
Posts: 54
Followers: 1

Kudos [?]: 0 [0], given: 0

Re: Sqrt Mod X [#permalink]  29 Jul 2007, 14:35
Robin in NC wrote:
abhi_ferrari wrote:
Robin in NC wrote:
abhi_ferrari wrote:
If x<0, then sqrt (-x |x|) = ?

1: -x
2: -1
3: 1
4: x
5: sqrt (x)

I get -x. (the opposite of x, in this case a positive number, since x is negative)

Sqrt(-x lxl) If x is <0, -x is positive. so -x and lxl are equal, together they equal -(the opposite of)x^2. Since the square root is positive, it will be the opposite of the negative number x, or -x.

Thanks, Robin. OA is infact A. I tried to put in value of x (say -2) and got 2 as the answer (so got x instead of -x). What am I doing wrong?

An answer of 2 would correspond to -x. Remember, x is a negative number, so -x is a positive number (the opposite of x) If x=-2, -x=2.

can't imagine I got this wrong. Thanks!
Re: Sqrt Mod X   [#permalink] 29 Jul 2007, 14:35
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# If x<0, then sqrt (-x |x|) = ? 1: -x 2: -1 3: 1 4: x 5:

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