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# If x<0, then sqrt(-x|x|) is -x -1 1 x sqrt(x

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Current Student
Joined: 31 Aug 2007
Posts: 371
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Kudos [?]: 63 [0], given: 1

If x<0, then sqrt(-x|x|) is -x -1 1 x sqrt(x [#permalink]  18 Nov 2007, 16:02
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If x<0, then sqrt(-x|x|) is

-x
-1
1
x
sqrt(x)
CEO
Joined: 17 Nov 2007
Posts: 3574
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 414

Kudos [?]: 2244 [0], given: 359

Expert's post
A. -x

for x<0: |x|=-x

f=sqrt(-x|x|)=sqrt((-x)*(-x))=sqrt(x^2)=|x|=-x
Manager
Joined: 08 Nov 2007
Posts: 99
Followers: 1

Kudos [?]: 1 [0], given: 0

Re: DS absolute value [#permalink]  18 Nov 2007, 16:28
young_gun wrote:
If x<0, then sqrt(-x|x|) is

-x
-1
1
x
sqrt(x)

Quick guess - A -x?

if x < 0, then x is negative, thus -x is positive, and |x| as the absolute value is a positive value - so it's equivalent is positive positive X^2 the square root of which is positive x. If x is negative, then -x is positive.
Current Student
Joined: 31 Aug 2007
Posts: 371
Followers: 1

Kudos [?]: 63 [0], given: 1

I guess I have not paid much attention to abs value concepts...does anyone know of any websites/posts that cover everything from the basic to the advanced? thx
Director
Joined: 13 Dec 2006
Posts: 520
Location: Indonesia
Followers: 6

Kudos [?]: 109 [0], given: 0

Clear A.

We know that the value is -x (from the question). So irrespective of any mathmatical calculation its value will remains the same.

Amar
Intern
Joined: 11 Jun 2007
Posts: 22
Followers: 0

Kudos [?]: 14 [0], given: 0

Guys, does n't this have to be -X instead of X ?
If it were -X and let us say we pick a value of -3 for X (because X < 0), then the result would be -(-3) = 3. This does not agree with what was given in the question.

Please explain if my approach was wrong.
Intern
Joined: 11 Jun 2007
Posts: 22
Followers: 0

Kudos [?]: 14 [0], given: 0

Is n't OA: D?
Please see my previous post above...
Manager
Joined: 03 Sep 2006
Posts: 233
Followers: 1

Kudos [?]: 7 [0], given: 0

Actually, I'm the second one who also thinks that the answer should be X ..

"The square of any positive or negative number is positive, and the square of 0 is 0. Therefore, no negative number can have a real square root. "
http://en.wikipedia.org/wiki/Square_roo ... ex_numbers
CEO
Joined: 17 Nov 2007
Posts: 3574
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 414

Kudos [?]: 2244 [0], given: 359

Expert's post
ok

definition:

f=|x| ==> 1. x>=0: f=x 2. x<0: f=-x

therefore on should use -x instead |x| in the case x<0
.......

let x=-10
sqrt(-x|x|)=sqrt(-(-10)*|-10|)=sqrt(-(-10)*(10))=sqrt(-(-100))=sqrt(100)=10=-x
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# If x<0, then sqrt(-x|x|) is -x -1 1 x sqrt(x

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