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Re: if x<0, what is the value of ^1/4+(-x*|x|)^1/2 i guess [#permalink]
[(x-3)^4]^1/4 how does it evaluate to -x+3??


I thought 4 and 1/4 cancelled themselves.
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Re: if x<0, what is the value of ^1/4+(-x*|x|)^1/2 i guess [#permalink]
rajiv_av wrote:
[(x-3)^4]^1/4 how does it evaluate to -x+3??


I thought 4 and 1/4 cancelled themselves.


but we are given that x<0..

if you cancelled 4 and 1/4, you get |x-3| not x-3..


So x-3<0... |x-3| = -x+3
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Re: if x<0, what is the value of ^1/4+(-x*|x|)^1/2 i guess [#permalink]
[(x-3)^4]^1/4+(-x*|x|)^1/2

-x+3 + (-x*|x|)^1/2

-x+3 + (x^2)^1/2

-x+3-x
-2x+3


We have to invert the signs because x is negative...



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