Bunuel wrote:
If x<0, y>0, and |x| > |y|, which of the following must be true?
A. x > y
B. y^2 > x^2
C. x^3 > y^2
D. –x < y
E. x < –y
Kudos for a correct solution.
Translate:
x < 0 --> x is negative
y > 0 --> y is positive
|x| > |y| --> the "positive" value of x, -(-x), is greater than y. Magnitude of x > magnitude of y
Or, x is more negative than y is positive: on the number line, x's distance from 0, to the left, is farther than y's distance from 0, to the right.
Pick numbers and check answers.
x = -3, y = 2
Plug inA. x > y: FALSE. -3 is not > 2
B. y^2 > x^2: FALSE. 4 is not > than 9
C. x^3 > y^2: FALSE. -27 is not greater than 4
D. –x < y. FALSE. -(-3) = 3. 3 is not less than 2
E. x < –y: TRUE. -3 is less than -2
Answer E
Assess signs x = -3, y = +2
A. x > y:
(-) > (+)?? NO
B. y^2 > x^2. Integers raised to even powers = positive.
Small (+) > Bigger (+)?? NO
C. x^3 > y^2: (-) raised to odd power = negative.
(-) > (+)?? NO
D. –x < y. For (x), the negative, or opposite (which is one thing the "-" sign means), of a negative is positive. So
bigger positive < smaller positive?? NO
E. x < –y. For y, the negative of a positive is negative.
More negative < less negative? YES.
<--[-3]---[-2]-------[0]-->
More to the left of zero = smaller
Answer E
-3 < 2 then by multiplying by -1 i get 3 > - 2 and since y>0, hence it cant be true. Am i thinking correctly ?