if |x+1|^2 =16 and (y-5)^2 =4, then what is the value of : Quant Question Archive [LOCKED]
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# if |x+1|^2 =16 and (y-5)^2 =4, then what is the value of

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if |x+1|^2 =16 and (y-5)^2 =4, then what is the value of [#permalink]

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19 Feb 2004, 08:32
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

if |x+1|^2 =16 and (y-5)^2 =4, then what is the value of x/y?

1. y > x
2. y/x > 0
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19 Feb 2004, 08:50
I got C
X = ( -5,3)
Y = (1,9)
A) insufficient because y=1>-5 and y=9>3
B) y/x > 0 then y=1 x=3 or y=9 and x=3

Combine you get y=9 and x=3
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19 Feb 2004, 19:12
if |x+1|^2 =16 and (y-5)^2 =4, then what is the value of x/y?

1. y > x
2. y/x > 0

Let us look at the given equations

1) |x+1|^2=16, this gives 2 values of x , 3,-5 .......
2) (y-5)^2=4, this gives us only one value of y i.e 7

Let us look at the statement

A) Emmm..... y is always greater that X or in other words 7 is always greter than -5 and 3 --- not good enough to find x

B) if x is negetive then it will be the value y/x is smaller than 0, if x is +ve then is greater than 0. Hence we have only one possible value of x which wud be 3.

C) Not required since statement 2 alone is sufficient

D) Statement A cannot satisfy (Hence ruled out) .

E) Not required

I hope this is correct.
Regards
Senior Manager
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20 Feb 2004, 03:50
Ans is C.
Simplifing the given data:
|x+1|^2 = 16 => |x+1| = +4 only => (x+1) = +or -4. Therefore, x =3 or -5.

(y-5)^2 = 4 => (y-5) = + or -2. Therefore, y = 7 or 3.

Statement 1 , y > x , is not sufficient since if, for example , x = -5, then y = 7 or y =3, and x/y will have 2 different values.

Statement 2 is insufficient since it merely suggests that x and y have the same sign.
combining the 2 statements implies that y=7 and x = -5 . Therefore, x/y = -5/7.

rgds,
batli
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20 Feb 2004, 13:35
[...]
Statement 2 is insufficient since it merely suggests that x and y have the same sign.
[...]

If you establish that x and y have the same sign and you have already established that y can only take positive values (7 or 3), doesn't this lead to x being positive?

In that case the answer should be B.
20 Feb 2004, 13:35
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