Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

if |x+1|^2 =16 and (y-5)^2 =4, then what is the value of x/y?

1. y > x
2. y/x > 0

Let us look at the given equations

1) |x+1|^2=16, this gives 2 values of x , 3,-5 .......
2) (y-5)^2=4, this gives us only one value of y i.e 7

Let us look at the statement

A) Emmm..... y is always greater that X or in other words 7 is always greter than -5 and 3 --- not good enough to find x

B) if x is negetive then it will be the value y/x is smaller than 0, if x is +ve then is greater than 0. Hence we have only one possible value of x which wud be 3.

C) Not required since statement 2 alone is sufficient

Ans is C.
Simplifing the given data:
|x+1|^2 = 16 => |x+1| = +4 only => (x+1) = +or -4. Therefore, x =3 or -5.

(y-5)^2 = 4 => (y-5) = + or -2. Therefore, y = 7 or 3.

Statement 1 , y > x , is not sufficient since if, for example , x = -5, then y = 7 or y =3, and x/y will have 2 different values.

Statement 2 is insufficient since it merely suggests that x and y have the same sign.
combining the 2 statements implies that y=7 and x = -5 . Therefore, x/y = -5/7.

[...]
Statement 2 is insufficient since it merely suggests that x and y have the same sign.
[...]

If you establish that x and y have the same sign and you have already established that y can only take positive values (7 or 3), doesn't this lead to x being positive?

Originally posted on MIT Sloan School of Management : We are busy putting the final touches on our application. We plan to have it go live by July 15...