If x - 1/3^7 - 1/3^8 - 1/3^9 = 1/3^9, then x = 2/3^4 2/3^5 : Quant Question Archive [LOCKED]
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# If x - 1/3^7 - 1/3^8 - 1/3^9 = 1/3^9, then x = 2/3^4 2/3^5

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Senior Manager
Joined: 05 Oct 2008
Posts: 274
Followers: 3

Kudos [?]: 379 [0], given: 22

If x - 1/3^7 - 1/3^8 - 1/3^9 = 1/3^9, then x = 2/3^4 2/3^5 [#permalink]

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08 Nov 2008, 22:21
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x - 1/3^7 - 1/3^8 - 1/3^9 = 1/3^9, then x =

2/3^4
2/3^5
1/3^5
1/3^7
2/3^10

If I solve this problem through the longer route I get
x = 9+18+6+2/3^7 = 35/3^7

Can anyone help me to pick my mistake?

Last edited by study on 09 Nov 2008, 08:40, edited 1 time in total.
Current Student
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Schools: Wharton'11 HBS'12
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Re: Fractions Simple [#permalink]

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08 Nov 2008, 23:10
hmm

i get x=2/3^9 + 3/3^9+9/3^9=14/3^9

i am missing a trick..
SVP
Joined: 17 Jun 2008
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Re: Fractions Tough [#permalink]

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09 Nov 2008, 10:45
study, can you plz check if there is a typo in the question? In the current form, even I got 14/3^9.

If the question is asking for an approx x, then it could be 1/3^7.
Re: Fractions Tough   [#permalink] 09 Nov 2008, 10:45
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# If x - 1/3^7 - 1/3^8 - 1/3^9 = 1/3^9, then x = 2/3^4 2/3^5

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