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because to cancel out your root you have to raise the same to the exponent of the same and at the same time raise the other part of the equation.

For instance: if you have √x= 4 rise to power of 2 both side; so you'll have x=16 or 3√x=4 then you'll have x=64 (rise to power of 3).

So we have x=6^6; of course in our case we do not need to obtain 6^6 (46656). we care about to substitute this value to our x and then resolve our problem. It was simple but me too was confused looking at the problem.

I ask to Bunuel to correct me if I'm wrong. _________________

In such cases i always try to find some simple number for which i am sure and make simple but similar calculation. For example in our case we have x^(1/6)=6 from a glance it is difficult to get what is this number, but if we take \(\sqrt{x}\)=2 we see that x is 4, because x^1/2=2 is the same as to say 2 multiplied by itself once. In our case we have x^(1/6)=6 using our logic that means x=6^6. In the second expression we have (x^6)^1/2 ---> (x)^6*1/2=x^3

Now the easiest part, since we know that x=6^6 then x^3=(6^6)^3=6^18

Answer choice D. _________________

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Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

So, my final tally is in. I applied to three b schools in total this season: INSEAD – admitted MIT Sloan – admitted Wharton – waitlisted and dinged No...

A few weeks ago, the following tweet popped up in my timeline. thanks @Uber_Mumbai for showing me what #daylightrobbery means!I know I have a choice not to use it...

“This elective will be most relevant to learn innovative methodologies in digital marketing in a place which is the origin for major marketing companies.” This was the crux...