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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]
01 Apr 2012, 06:20

Expert's post

TomB wrote:

bunnel

how did you come x=6^6,please explain

because to cancel out your root you have to raise the same to the exponent of the same and at the same time raise the other part of the equation.

For instance: if you have √x= 4 rise to power of 2 both side; so you'll have x=16 or 3√x=4 then you'll have x=64 (rise to power of 3).

So we have x=6^6; of course in our case we do not need to obtain 6^6 (46656). we care about to substitute this value to our x and then resolve our problem. It was simple but me too was confused looking at the problem.

I ask to Bunuel to correct me if I'm wrong. _________________

Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]
06 Jun 2013, 06:20

In such cases i always try to find some simple number for which i am sure and make simple but similar calculation. For example in our case we have x^(1/6)=6 from a glance it is difficult to get what is this number, but if we take \(\sqrt{x}\)=2 we see that x is 4, because x^1/2=2 is the same as to say 2 multiplied by itself once. In our case we have x^(1/6)=6 using our logic that means x=6^6. In the second expression we have (x^6)^1/2 ---> (x)^6*1/2=x^3

Now the easiest part, since we know that x=6^6 then x^3=(6^6)^3=6^18

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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]
17 May 2015, 11:04

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