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If X>1 and Y>1, is X<Y? (1) X?/(XY+X)<1 (2)

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Manager
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If X>1 and Y>1, is X<Y? (1) X?/(XY+X)<1 (2) [#permalink] New post 21 Mar 2006, 10:09
If X>1 and Y>1, is X<Y?
(1) X?/(XY+X)<1
(2) XY/Y?-Y<1
VP
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Re: Xs and Ys [#permalink] New post 24 Mar 2006, 16:43
jcgoodchild wrote:
If X>1 and Y>1, is X<Y?
(1) X?/(XY+X)<1
(2) XY/Y?-Y<1


from i
X / (XY + X) < 1
X < XY + X
0 < XY
so not enough.....

from ii,

(XY/Y)-(Y)<1
XY< Y^2
X< Y

suff.

B.
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 [#permalink] New post 27 Mar 2006, 18:07
X?<XY+X

Since x>1 you could cancel x out

1. ?<y+1 not sufficient
2. for the same reason as one cancel y out.
x<?-1 not sufficient

If you combine both

Not sufficient i.e use 3 for 3<y+1 you get=y>2 and x<3-1 you get x<2

Hence Y>x

Answer is C

What's the answer?
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 [#permalink] New post 27 Mar 2006, 18:08
Sufficient answer C
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 [#permalink] New post 27 Mar 2006, 18:29
What if the unknown ? is -3 or ? < 0.

We know x & y are positive so they can be cancelled out, but we don't know the unknown is -ve or +ve.

So the answer can be (E)
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Re: Xs and Ys [#permalink] New post 27 Mar 2006, 19:00
Professor wrote:
jcgoodchild wrote:
If X>1 and Y>1, is X<Y?
(1) X?/(XY+X)<1
(2) XY/Y?-Y<1


from i, X / (XY + X) < 1
X < XY + X
0 < XY. so not enough.....

from ii, (XY/Y)-(Y)<1
XY< Y^2
X< Y. suff. B.


update:

from i X/(XY + X) < 1
X < XY + X
0 < XY
so not enough.....

from ii, (XY/Y)-(Y)<1
XY< Y + Y^2
X< Y (1+Y)
X< (1+Y). insuff.

so from i and ii also not suff E too.
Manager
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 [#permalink] New post 28 Mar 2006, 06:05
I think for any value you test you need to make sure that

X > 1 and Y> 1 so you can't test -3

What's the OA
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 [#permalink] New post 28 Mar 2006, 06:09
I am not able to understand this question.
What does all this question mark stand for in the choices.
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 [#permalink] New post 28 Mar 2006, 07:29
I think they stand for unknown no.s
  [#permalink] 28 Mar 2006, 07:29
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