Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: if X>1 and Y>1, is X<Y? (1) [#permalink]
21 Jun 2012, 01:23

1

This post received KUDOS

Expert's post

pavanpuneet wrote:

Can someone confirm the OA, it is B according to me as well;

For the following question the answer is B.

If x>1 and y>1, is x<y?

(1) \frac{x^2}{xy+x}<1 --> reduce by x: \frac{x}{y+1}<1 --> cross multiply, notice that we can safely do that since y+1>0: x<y+1 --> if x=2 and y=2, then the answer is NO but if x=2 and y=3, then the answer is YES. Not sufficient.

(2) \frac{xy}{y^2-y}<1 --> reduce by y: \frac{x}{y-1}<1 --> cross multiply, notice that we can safely do that since y-1>0: x<y-1 --> x+1<y (y is more than x plus 1) --> y>x. Sufficient.

Re: if X>1 and Y>1, is X<Y? (1) [#permalink]
21 Jun 2012, 01:23

Expert's post

pavanpuneet wrote:

Can someone confirm the OA, it is B according to me as well;

If (2) is \frac{xy}{y^2}-y<1, then the answer is indeed E.

If x>1 and y>1, is x<y?

(1) \frac{x^2}{xy+x}<1 --> reduce by x: \frac{x}{y+1}<1 --> cross multiply, notice that we can safely do that since y+1>0: x<y+1 --> if x=2 and y=2, then the answer is NO but if x=2 and y=3, then the answer is YES. Not sufficient.

(2) \frac{xy}{y^2}-y<1 --> reduce by y: \frac{x}{y}-y<1 --> x<y^2 --> if x=2 and y=2, then the answer is NO but if x=2 and y=3, then the answer is YES. Not sufficient.

(1)+(2) If x=2 and y=3, then the answer is YES but If x=2 and y=\sqrt{3}\approx{1.7} (notice that this set of numbers satisfy both statements), then the answer is NO. Not Sufficient.

I couldn’t help myself but stay impressed. young leader who can now basically speak Chinese and handle things alone (I’m Korean Canadian by the way, so...