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If x>1 and y>1, is x<y?

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If x>1 and y>1, is x<y? [#permalink] New post 02 May 2011, 04:29
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A
B
C
D
E

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Question Stats:

18% (01:25) correct 82% (01:01) wrong based on 28 sessions
If x>1 and y>1, is x<y?

(1) x^2/(xy+x) <1
(2) xy/(y^2-y) <1
[Reveal] Spoiler: OA

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Re: Inequality [#permalink] New post 02 May 2011, 04:42
I think its B. The answer is YES

Reason :
S2 reduces to x / (y - 1) < 1

or x + 1 < y

I can cross multiply since x and y are both positive

jamifahad wrote:
if X>1 and Y>1, is X<Y?
(1) (X^2/(XY+X)) <1
(2) (XY/Y^2-Y) <1
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Re: Inequality [#permalink] New post 02 May 2011, 17:19
(1)

x < y+1

Not sufficient

(2)

x < y - 1

=> x+1 < y

=> y-x > 1

=> x < y

Sufficient

Answer - B

Could you please recheck the OA/OE ?
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Re: Inequality [#permalink] New post 12 Aug 2011, 00:02
a x=y=2 N x=2,y=3 Y not sufficient.

b x=2,y=4 Y x=1.1,y= 2.2 Y sufficient.

B it is.
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Re: if X>1 and Y>1, is X<Y? (1) [#permalink] New post 21 Jun 2012, 01:23
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pavanpuneet wrote:
Can someone confirm the OA, it is B according to me as well;


For the following question the answer is B.

If x>1 and y>1, is x<y?

(1) \frac{x^2}{xy+x}<1 --> reduce by x: \frac{x}{y+1}<1 --> cross multiply, notice that we can safely do that since y+1>0: x<y+1 --> if x=2 and y=2, then the answer is NO but if x=2 and y=3, then the answer is YES. Not sufficient.

(2) \frac{xy}{y^2-y}<1 --> reduce by y: \frac{x}{y-1}<1 --> cross multiply, notice that we can safely do that since y-1>0: x<y-1 --> x+1<y (y is more than x plus 1) --> y>x. Sufficient.

Answer: B.
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Re: if X>1 and Y>1, is X<Y? (1) [#permalink] New post 21 Jun 2012, 01:23
Expert's post
pavanpuneet wrote:
Can someone confirm the OA, it is B according to me as well;


If (2) is \frac{xy}{y^2}-y<1, then the answer is indeed E.

If x>1 and y>1, is x<y?

(1) \frac{x^2}{xy+x}<1 --> reduce by x: \frac{x}{y+1}<1 --> cross multiply, notice that we can safely do that since y+1>0: x<y+1 --> if x=2 and y=2, then the answer is NO but if x=2 and y=3, then the answer is YES. Not sufficient.

(2) \frac{xy}{y^2}-y<1 --> reduce by y: \frac{x}{y}-y<1 --> x<y^2 --> if x=2 and y=2, then the answer is NO but if x=2 and y=3, then the answer is YES. Not sufficient.

(1)+(2) If x=2 and y=3, then the answer is YES but If x=2 and y=\sqrt{3}\approx{1.7} (notice that this set of numbers satisfy both statements), then the answer is NO. Not Sufficient.

Answer: E.
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RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: if X>1 and Y>1, is X<Y? (1)   [#permalink] 21 Jun 2012, 01:23
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