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If x>1 and y>1, is x<y? [#permalink]
 02 May 2011, 05:29
Question Stats:
23% (01:25) correct
76% (01:01) wrong based on 21 sessions
If x>1 and y>1, is x<y? (1) x^2/(xy+x) <1 (2) xy/(y^2-y) <1
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I think its B. The answer is YES Reason : S2 reduces to x / (y - 1) < 1 or x + 1 < y I can cross multiply since x and y are both positive jamifahad wrote: if X>1 and Y>1, is X<Y?
(1) (X^2/(XY+X)) <1
(2) (XY/Y^2-Y) <1
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(1) x < y+1 Not sufficient (2) x < y - 1 => x+1 < y => y-x > 1 => x < y Sufficient Answer - B Could you please recheck the OA/OE ?
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a x=y=2 N x=2,y=3 Y not sufficient. b x=2,y=4 Y x=1.1,y= 2.2 Y sufficient. B it is.
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Re: if X>1 and Y>1, is X<Y? (1) [#permalink]
21 Jun 2012, 02:23
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Re: if X>1 and Y>1, is X<Y? (1) [#permalink]
21 Jun 2012, 02:23
pavanpuneet wrote: Can someone confirm the OA, it is B according to me as well; If (2) is \frac{xy}{y^2}-y<1, then the answer is indeed E. If x>1 and y>1, is x<y?(1) \frac{x^2}{xy+x}<1 --> reduce by x: \frac{x}{y+1}<1 --> cross multiply, notice that we can safely do that since y+1>0: x<y+1 --> if x=2 and y=2, then the answer is NO but if x=2 and y=3, then the answer is YES. Not sufficient. (2) \frac{xy}{y^2}-y<1 --> reduce by y: \frac{x}{y}-y<1 --> x<y^2 --> if x=2 and y=2, then the answer is NO but if x=2 and y=3, then the answer is YES. Not sufficient. (1)+(2) If x=2 and y=3, then the answer is YES but If x=2 and y=\sqrt{3}\approx{1.7} (notice that this set of numbers satisfy both statements), then the answer is NO. Not Sufficient. Answer: E.
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Re: if X>1 and Y>1, is X<Y? (1)
[#permalink]
21 Jun 2012, 02:23
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