If X > 1 and Y > 1, is X < Y A. X^2/(XY+X) < 1 : Quant Question Archive [LOCKED]
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# If X > 1 and Y > 1, is X < Y A. X^2/(XY+X) < 1

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Director
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If X > 1 and Y > 1, is X < Y A. X^2/(XY+X) < 1 [#permalink]

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25 Jul 2007, 21:03
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If X > 1 and Y > 1, is X < Y
A. X^2/(XY+X) < 1
B. XY/Y^2-Y < 1
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Last edited by bewakoof on 25 Jul 2007, 21:36, edited 1 time in total.
Director
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Re: Set 26 Q's Wrong No. 3 [#permalink]

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25 Jul 2007, 21:34
bewakoof wrote:
If X > 1 and Y > 1, is X < Y

A. X^2(XY+X) < 1
B. XY/Y^2-Y < 1

st 1 is not possible.

make sure it is correct.....
Director
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Re: Set 26 Q's Wrong No. 3 [#permalink]

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25 Jul 2007, 21:40
bewakoof wrote:
If X > 1 and Y > 1, is X < Y

A. X^2/(XY+X) < 1
B. XY/Y^2-Y < 1

B. x/(y-1) is still smaller than 1, then x<y.
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25 Jul 2007, 21:52
St1:
X^2/(XY+X) < 1
x^2/x(y+1) < 1
x/y+1

We know x < y+1 in order for result to be a positive fraction.
If x = 5, y could be 5 and 5/6 < 1 but x = y or x = 5, y = 7 and 5/8 < 1. Insufficient.

St2:
xy/y(y-1) < 1
x/y-1 <1> y for the fraction to be less than 1. Sufficient.,

B for me
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25 Jul 2007, 22:00
B

x < y-1 => x < y
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27 Jul 2007, 11:31
ywilfred wrote:
St1:
X^2/(XY+X) < 1
x^2/x(y+1) < 1
x/y+1

We know x < y+1 in order for result to be a positive fraction.
If x = 5, y could be 5 and 5/6 < 1 but x = y or x = 5, y = 7 and 5/8 < 1. Insufficient.

St2:
xy/y(y-1) < 1
x/y-1 <1> y for the fraction to be less than 1. Sufficient.,

B for me

Can you explain the bold portion.

For statement 1: we get x/(y+1)<1 = x<(y+1) ..So we get x<y which is true..So shouldn't the answer be D....
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27 Jul 2007, 11:42
I get E, but I'm not good at these
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27 Jul 2007, 15:06
smily_buddy wrote:
ywilfred wrote:
St1:
X^2/(XY+X) < 1
x^2/x(y+1) < 1
x/y+1

We know x < y+1 in order for result to be a positive fraction.
If x = 5, y could be 5 and 5/6 < 1 but x = y or x = 5, y = 7 and 5/8 < 1. Insufficient.

St2:
xy/y(y-1) < 1
x/y-1 <1> y for the fraction to be less than 1. Sufficient.,

B for me

Can you explain the bold portion.

For statement 1: we get x/(y+1)<1 = x<(y+1) ..So we get x<y which is true..So shouldn't the answer be D....

x could be equal to Y for st. 1.
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27 Jul 2007, 17:30
D for me.

Stmt 1: x^2/xy+x<1 = x^2<xy+x = x<y. (factor out the x's)

Stmt 2: xy/y(y-1)<1 = xy<y(y-1) = xy<y^2-y = x<y (factor out the y's)
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15 Aug 2007, 17:20
Robin in NC wrote:
D for me.

Stmt 1: x^2/xy+x<1 = x^2<xy+x = x<y. (factor out the x's)

Stmt 2: xy/y(y-1)<1 = xy<y(y-1) = xy<y^2-y = x<y (factor out the y's)

the bolded equation becomes x<y+1 ...which is insuff..x=y..we dont know..
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16 Aug 2007, 12:20
B according to me

from 1: x^2/xy+x<1 = x^2<xy+x = x<y+1.... Cant find out !

From 2: xy/y(y-1)<1 = xy<y(y-1) = xy<y^2-y = x<y-1 = x+1< y so x<y
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Re: Set 26 Q's Wrong No. 3 [#permalink]

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16 Aug 2007, 12:42
bewakoof wrote:
If X > 1 and Y > 1, is X < Y
A. X^2/(XY+X) < 1
B. XY/Y^2-Y < 1

B.

(1) Final equation:
x<y+1
Say y = 2, you would get x<3, which can or cannot be <2
INSUFFICIENT.

(2) Final equation:
x<y-1
Say y=3, you would get x<2, which will always be <3.
SUFFICIENT.
Director
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16 Aug 2007, 14:01
(1) => x-y<1 i.e difference can be 0.5 (so x gt y) or -0.5 (i.e. x lt y) INSUFF
(2) => x-y<-1...means y will always be greater than x.
SUFF

ANS B.
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16 Aug 2007, 14:46
B for me too...I am finally getting better at these...they seem complex when you read the stem and the statements, but when you actually sit down an think about 'em..the answer jumps out at ya
16 Aug 2007, 14:46
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