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# If X > 1 and Y > 1, is X < Y A. X^2/(XY+X) < 1

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Director
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If X > 1 and Y > 1, is X < Y A. X^2/(XY+X) < 1 [#permalink]  25 Jul 2007, 21:03
If X > 1 and Y > 1, is X < Y
A. X^2/(XY+X) < 1
B. XY/Y^2-Y < 1
_________________

Success is my only option, failure is not -- Eminem

Last edited by bewakoof on 25 Jul 2007, 21:36, edited 1 time in total.
Director
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Re: Set 26 Q's Wrong No. 3 [#permalink]  25 Jul 2007, 21:34
bewakoof wrote:
If X > 1 and Y > 1, is X < Y

A. X^2(XY+X) < 1
B. XY/Y^2-Y < 1

st 1 is not possible.

make sure it is correct.....
Director
Joined: 26 Feb 2006
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Re: Set 26 Q's Wrong No. 3 [#permalink]  25 Jul 2007, 21:40
bewakoof wrote:
If X > 1 and Y > 1, is X < Y

A. X^2/(XY+X) < 1
B. XY/Y^2-Y < 1

B. x/(y-1) is still smaller than 1, then x<y.
GMAT Club Legend
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St1:
X^2/(XY+X) < 1
x^2/x(y+1) < 1
x/y+1

We know x < y+1 in order for result to be a positive fraction.
If x = 5, y could be 5 and 5/6 < 1 but x = y or x = 5, y = 7 and 5/8 < 1. Insufficient.

St2:
xy/y(y-1) < 1
x/y-1 <1> y for the fraction to be less than 1. Sufficient.,

B for me
Senior Manager
Joined: 28 Jun 2007
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B

x < y-1 => x < y
Manager
Joined: 30 Jan 2006
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ywilfred wrote:
St1:
X^2/(XY+X) < 1
x^2/x(y+1) < 1
x/y+1

We know x < y+1 in order for result to be a positive fraction.
If x = 5, y could be 5 and 5/6 < 1 but x = y or x = 5, y = 7 and 5/8 < 1. Insufficient.

St2:
xy/y(y-1) < 1
x/y-1 <1> y for the fraction to be less than 1. Sufficient.,

B for me

Can you explain the bold portion.

For statement 1: we get x/(y+1)<1 = x<(y+1) ..So we get x<y which is true..So shouldn't the answer be D....
Senior Manager
Joined: 17 Jul 2007
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I get E, but I'm not good at these
Senior Manager
Joined: 28 Jun 2007
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smily_buddy wrote:
ywilfred wrote:
St1:
X^2/(XY+X) < 1
x^2/x(y+1) < 1
x/y+1

We know x < y+1 in order for result to be a positive fraction.
If x = 5, y could be 5 and 5/6 < 1 but x = y or x = 5, y = 7 and 5/8 < 1. Insufficient.

St2:
xy/y(y-1) < 1
x/y-1 <1> y for the fraction to be less than 1. Sufficient.,

B for me

Can you explain the bold portion.

For statement 1: we get x/(y+1)<1 = x<(y+1) ..So we get x<y which is true..So shouldn't the answer be D....

x could be equal to Y for st. 1.
Manager
Joined: 27 May 2007
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D for me.

Stmt 1: x^2/xy+x<1 = x^2<xy+x = x<y. (factor out the x's)

Stmt 2: xy/y(y-1)<1 = xy<y(y-1) = xy<y^2-y = x<y (factor out the y's)
Current Student
Joined: 28 Dec 2004
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Schools: Wharton'11 HBS'12
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Robin in NC wrote:
D for me.

Stmt 1: x^2/xy+x<1 = x^2<xy+x = x<y. (factor out the x's)

Stmt 2: xy/y(y-1)<1 = xy<y(y-1) = xy<y^2-y = x<y (factor out the y's)

the bolded equation becomes x<y+1 ...which is insuff..x=y..we dont know..
Manager
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B according to me

from 1: x^2/xy+x<1 = x^2<xy+x = x<y+1.... Cant find out !

From 2: xy/y(y-1)<1 = xy<y(y-1) = xy<y^2-y = x<y-1 = x+1< y so x<y
VP
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Re: Set 26 Q's Wrong No. 3 [#permalink]  16 Aug 2007, 12:42
bewakoof wrote:
If X > 1 and Y > 1, is X < Y
A. X^2/(XY+X) < 1
B. XY/Y^2-Y < 1

B.

(1) Final equation:
x<y+1
Say y = 2, you would get x<3, which can or cannot be <2
INSUFFICIENT.

(2) Final equation:
x<y-1
Say y=3, you would get x<2, which will always be <3.
SUFFICIENT.
Director
Joined: 18 Jul 2006
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(1) => x-y<1 i.e difference can be 0.5 (so x gt y) or -0.5 (i.e. x lt y) INSUFF
(2) => x-y<-1...means y will always be greater than x.
SUFF

ANS B.
Manager
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B for me too...I am finally getting better at these...they seem complex when you read the stem and the statements, but when you actually sit down an think about 'em..the answer jumps out at ya
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