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If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

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If x = -1, then (x^4 - x^3 + x^2)/(x - 1) = [#permalink] New post 19 Dec 2012, 06:17
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If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

(A) -3/2
(B) -1/2
(C) 0
(D) 1/2
(E) 3/2
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Re: If x = -1, then (x^4 - x^3 + x^2)/(x - 1) = [#permalink] New post 19 Dec 2012, 06:19
Walkabout wrote:
If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

(A) -3/2
(B) -1/2
(C) 0
(D) 1/2
(E) 3/2


\frac{x^4 - x^3 + x^2)}{x - 1} =\frac{(-1)^4 - (-1)^3 + (-1)^2)}{-1 - 1} =\frac{1+1+1}{-2}=-\frac{3}{2}.

Answer: A.
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Re: If x = -1, then (x^4 - x^3 + x^2)/(x - 1) = [#permalink] New post 19 Dec 2012, 06:21
Walkabout wrote:
If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

(A) -3/2
(B) -1/2
(C) 0
(D) 1/2
(E) 3/2


=\frac{(-1)^{4}-(-1)^{3}+(-1)^{2}}{(-1-1)}=\frac{1+1+1}{-2}=-\frac{3}{2}

Answer: A
Re: If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =   [#permalink] 19 Dec 2012, 06:21
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