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If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

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If x = -1, then (x^4 - x^3 + x^2)/(x - 1) = [#permalink]  19 Dec 2012, 05:17
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82% (01:31) correct 18% (00:29) wrong based on 337 sessions
If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

(A) -3/2
(B) -1/2
(C) 0
(D) 1/2
(E) 3/2
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 28252
Followers: 4464

Kudos [?]: 45048 [0], given: 6640

Re: If x = -1, then (x^4 - x^3 + x^2)/(x - 1) = [#permalink]  19 Dec 2012, 05:19
Expert's post
If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

(A) -3/2
(B) -1/2
(C) 0
(D) 1/2
(E) 3/2

$$\frac{x^4 - x^3 + x^2)}{x - 1} =\frac{(-1)^4 - (-1)^3 + (-1)^2)}{-1 - 1} =\frac{1+1+1}{-2}=-\frac{3}{2}$$.

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Senior Manager
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Posts: 464
Concentration: Marketing, Finance
GMAT 1: Q V0
GPA: 3.23
Followers: 17

Kudos [?]: 276 [0], given: 11

Re: If x = -1, then (x^4 - x^3 + x^2)/(x - 1) = [#permalink]  19 Dec 2012, 05:21
If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

(A) -3/2
(B) -1/2
(C) 0
(D) 1/2
(E) 3/2

$$=\frac{(-1)^{4}-(-1)^{3}+(-1)^{2}}{(-1-1)}=\frac{1+1+1}{-2}=-\frac{3}{2}$$

_________________

Impossible is nothing to God.

Re: If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =   [#permalink] 19 Dec 2012, 05:21
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