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# If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

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If x = -1, then (x^4 - x^3 + x^2)/(x - 1) = [#permalink]

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19 Dec 2012, 05:17
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If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

(A) -3/2
(B) -1/2
(C) 0
(D) 1/2
(E) 3/2
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Re: If x = -1, then (x^4 - x^3 + x^2)/(x - 1) = [#permalink]

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19 Dec 2012, 05:19
If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

(A) -3/2
(B) -1/2
(C) 0
(D) 1/2
(E) 3/2

$$\frac{x^4 - x^3 + x^2)}{x - 1} =\frac{(-1)^4 - (-1)^3 + (-1)^2)}{-1 - 1} =\frac{1+1+1}{-2}=-\frac{3}{2}$$.

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Re: If x = -1, then (x^4 - x^3 + x^2)/(x - 1) = [#permalink]

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19 Dec 2012, 05:21
If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =

(A) -3/2
(B) -1/2
(C) 0
(D) 1/2
(E) 3/2

$$=\frac{(-1)^{4}-(-1)^{3}+(-1)^{2}}{(-1-1)}=\frac{1+1+1}{-2}=-\frac{3}{2}$$

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Re: If x = -1, then (x^4 - x^3 + x^2)/(x - 1) = [#permalink]

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28 Oct 2015, 06:51
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Re: If x = -1, then (x^4 - x^3 + x^2)/(x - 1) =   [#permalink] 28 Oct 2015, 06:51
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