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This is the answer in the book but I just don't get it..

Statement (1) tells us that there are x unique factors of x. In order for this to be true, EVERY integer between 1 and x, inclusive, must be a factor of x. Testing numbers, we can see that this property holds for 1 and for 2, but not for 3 or for 4. In fact, this property does not hold for any higher integer, because no integer x above 2 is divisible by x-I. Therefore, x = 1 or 2. However, the original problem stem told us that x > 1, so x must equal 2. SUFFICIENT. Statement (2) tells us that x plus any prime number larger than x is odd. Since x > 1, x must equal at least 2, so this includes only prime numbers larger than 2. Therefore, the prime number is odd, and x is even. However, this does not tell us which even number x could be. INSUFFICIENT. The correct answer is (A): Statement (1) is sufficient to answer the ques- tion, but Statement (2) is insufficient.

Re: If x > 1, what is the value ofinteger x? [#permalink]

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18 Mar 2011, 14:39

even i was confuse for the first time. But I think the answer explainations tells, if say x = 5, then it needs 5 unique factor, but for 5 it is only 1 and 5. For 4 it is 1,2, and 4. So for any number greater than 2 there is no way you can have as many factor as the number itself. hence it should be 2. I hope I interpreted right, but as I said it is a confusing question.

Re: If x > 1, what is the value ofinteger x? [#permalink]

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18 Mar 2011, 15:34

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Well here is how i would do it.

1. x has x factors

meaning if you take any integer , that should have that many factors

1 has 1 factor (i.e 1 , meets the criteria) 2 has 2 factors (i.e 1 and 2) 3 has 2 factors (i.e 1 and 3, doesnt meet the criteria, to satisfy this should have had 3 factors)

take any other number lets say 17 , to meet this criteria this should have 17 factors. not satisfied.

so only 1 and 2 satisfies the condition, then again in the question it says x has to be greater than 1 . so that rules out 1 . Hence x =2 .

So sufficient. 2. x + ( prime >x )has to be odd

primes (2,3,5,7,11....)

2+ (prime >2) = 2 +3 = odd (x could be 3) 2+5 = odd (x could be 5)

Not sufficient as there are more possible values for x.

Re: If x > 1, what is the value ofinteger x? [#permalink]

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18 Mar 2011, 19:13

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Expert's post

l0rrie wrote:

If x > 1, what is the value of integer x?

(1) There are x unique factors of x. (2) The sum of x and any prime number larger than x is odd.

First of all, it is not a very straight forward question. Definitely needs some thinking so relax...

Ques: What is the value of x? So we are looking for a single value of x.

First consider statement 2 since it is easier. x + prime number greater than x = odd There will be many many prime numbers greater than x. All prime numbers are odd except 2. So if you can add any prime number greater than x to x and get an odd number, it means x must be even. (because Even + Odd = Odd) So all statement 2 tells you is that x is even. It could be 2 or 4 or 6 etc

Now look at statement 1. There are x unique factors of x. Think of the first number greater than 1. 2 has 2 unique factors: 1 and 2 ( 2 is a prime number) What about 3? It has 2 unique factors: 1 and 3 (a prime number) 4 has 3 unique factors: 1, 2 , 4 Is it possible that any greater number x has x unique factors? No. Why? For x to have x unique factors, each number from 1 to x must be a factor of x. Say if 10 had 10 unique factors, each number 1, 2, 3, 4, 5..., 9,10 would have to be a factor of 10 (because factors are always positive integers) But can 9 be a factor of 10 i.e. can (x-1) be a factor of x? No. 2 consecutive positive integers share only one common factor i.e. 1. Why? Check out the post given below for the answer: question-from-practice-exam-78880.html#p847817

So statement 1 is enough to tell us that x is 2. _________________

Re: If x > 1, what is the value ofinteger x? [#permalink]

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19 Mar 2011, 03:34

Thanks everyone!! Really much appreciated, I get it now.. This has been extremely helpful.. I need to do a GMAT but it's been 6 years since I've studied maths.. And even in high school I was horrible so i'm really stressed about this.. Hopefully I'll get better haha.. Again, thanks!

If x > 1, what is the value of integer x? (1) There are x unique factors of x. ( what does that mean ?????? ) (2) The sum of x and any prime number larger than x is odd. thanks

They could have worded Statement 1 better, but it's just trying to tell you how many positive divisors x has. Here we learn that x has x positive divisors. If you just imagine a number for x (e.g. imagine the phrase "10 has 10 positive divisors", clearly absurd) you can probably see quickly that this is almost never true. For x to have x positive divisors, x would need to be divisible by *every* integer from 1 up to x inclusive. That will only happen if x = 1 or x = 2. Since x > 1, x must be 2, and Statement 1 is sufficient.

Statement 2 will be true for any even value of x (since any prime larger than x will be odd if x > 2), so is not helpful.

The answer is A. _________________

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If you are looking for online GMAT math tutoring, or if you are interested in buying my advanced Quant books and problem sets, please contact me at ianstewartgmat at gmail.com

Option A says x unique factors of x ... In my opinion there are only two integers whose unique factors are equal to themselves They are 1 = 1 and 2 = 1,2 And We need an integer greater that 1 so it has to be 2 Thus sufficient

Option B tells us that x+prime num larger that x = odd therefore 2 + 3 = 5 ...odd also if we suppose x= 4 then 4 +5 = 9...odd ....

therefore x can be any even number greater than 1 ...hence this option is insufficient

If x>1, what is the value of integer x? 1) There are x [#permalink]

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10 Aug 2011, 18:45

If x>1, what is the value of integer x?

1) There are x unique factors of x. 2) The sum of x and any prime number larger than x is odd.

The MGMAT book explains the answer as 1) S, 2) NS. They say that in order for statement one to be true, every integer between 1 and x, inclusive, must be a factor of x. By testing numbers, this holds true for 1 and 2, but not for 3 and 4. (Page 31 of the number properties guide if anyone cares to look).

Can someone please explain to me why this does not hold true for the numbers 3 and 4. Not sure what I am missing here.

Re: Odds and Evens - DS - Manhattan GMAT [#permalink]

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10 Aug 2011, 20:03

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jgonza8 wrote:

If x>1, what is the value of integer x?

x is an integer greater than 1. What is the value of x ? 1) There are x unique factors of x. This can happen for 2 only if x>1...because 2 has 2 factors - 1,2 All other values of x do not x unique factors - example - 3 has only 1 unique factors (1,3) other than 3 itself because\(3 = 1*3\) 4 has only 2 unique factors (1,2) other than 4 itself because \(4 = 1*2^2\) 5 has only 1 unique factors (1,5) other than 5 itself because \(5 = 1*5\) 6 has only 3 unique factors (1,2,3) other than 6 itself because \(6 = 1*2*3\) So A/D now 2) The sum of x and any prime number larger than x is odd. Let us substitute...x will only be even value because odd - odd = even 2+5 = 7 4+5 = 9 So multiple values...So B is not sufficient. So A will be the OA

The MGMAT book explains the answer as 1) S, 2) NS. They say that in order for statement one to be true, every integer between 1 and x, inclusive, must be a factor of x. By testing numbers, this holds true for 1 and 2, but not for 3 and 4. (Page 31 of the number properties guide if anyone cares to look).

Can someone please explain to me why this does not hold true for the numbers 3 and 4. Not sure what I am missing here. Have explained above.

Tell if you are not clear. _________________

Labor cost for typing this post >= Labor cost for pushing the Kudos Button http://gmatclub.com/forum/kudos-what-are-they-and-why-we-have-them-94812.html

Last edited by krishp84 on 12 Aug 2011, 18:18, edited 2 times in total.

Re: Odds and Evens - DS - Manhattan GMAT [#permalink]

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11 Aug 2011, 22:06

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the question asks what number is equal to the number of his unique factors. 1 has 1 unique factor so 1 is equal to the number of his unique factors. 2 is equal to the number of his unique factors. 3 has only 2 unique factors , 4 and 5 have 2, 11 only 2 and so on.

so the only numbers equal to their unique fators are 1 and 2 . the condition is that x>1 so only 2 applies.

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Re: Odds and Evens - DS - Manhattan GMAT [#permalink]

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12 Aug 2011, 18:11

Sovjet wrote:

Why are you guys not considering the number itself as a factor?

To me:

4 has 3 unique factors (not 2) - 1,2,4 5 has 2 unique factors - 1,5 6 has 4 (not 3) unique factors - 1,2,3,6

It doesn't change the answer or anything, but the number itself is a unique factor. They weren't asking for the prime roots.

Yes - This is correct.....I had missed this...

And why does this not affect the answer ? Because Total number of unique factors for any number = 1 + Total number of unique factors other than the number Adding 1 does not affect the count because we are any way comparing the (actual count - 1) However my solution will be wrong if applied for larger numbers say 12 \(12 = 3 *2^2\) Number of unique factors other than \(1 = (1+1)*(2+1) - 1 = 2*3 - 1 = 5\)

You can also calculate and confirm this : Factors of 12 - 1,2,3,4,6,12 Factors of 12 other than 1 = 2,3,4,6,12 All are unique Total number of such unique factors other than 1 = 5

So - Substitute smartly because this is a DATA SUFFICIENCY and NOT PROBLEM SOLVING question. I am editing my post to correct this .... _________________

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Re: If x > 1, what is the value ofinteger x? [#permalink]

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19 Sep 2013, 14:37

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Re: If x > 1, what is the value of integer x? [#permalink]

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20 Sep 2013, 00:34

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If x>1, what is the value of integer x?

(1) There are x unique factors of x --> x to have x distinct positive factors it must be divisible by EVERY integer from 1 to x, inclusive but x can not be divisible by x-1 unless x=2, for example 3 is not divisible by 2, 4 is not divisible by 3, etc, but 2 is divisible by 1 (other value of x which has x distinct positive factors (1) is excluded by the stem as x>1). So this statement implies that x=2. Sufficient.

(2) The sum of x and any prime number larger than x is odd --> x+prime=odd, now as x itself is more than 1 then prime more than x cannot be 2 thus it's odd and we have x+odd prime=odd --> x=even, so x could be ANY even number. Not sufficient.

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