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# If ((x^2 – 2x – 2)/2) = 3, what is the one possible value of

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If ((x^2 – 2x – 2)/2) = 3, what is the one possible value of [#permalink]  03 May 2013, 20:00
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If

x2 – 2x – 2
-------------- = 3
2

what is one possible value of x?

A) -4

B) -3

C) -2

D) 2

E) 3

I know this is a rather simple problem that I came across online, but I cannot seem to figure out the best/quickest way to solve it. I don't have the answer, but any help would be greatly appreciated!

~ Im2bz2p345
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Re: If ((x^2 – 2x – 2)/2) = 3, what is the one possible value of [#permalink]  03 May 2013, 22:57
Im2bz2p345 wrote:
If

x2 – 2x – 2
-------------- = 3
2

what is one possible value of x?

A) -4

B) -3

C) -2

D) 2

E) 3

I know this is a rather simple problem that I came across online, but I cannot seem to figure out the best/quickest way to solve it. I don't have the answer, but any help would be greatly appreciated!

~ Im2bz2p345

x^2-2x-2 = 6

orx^2-2x+1 = 9

or (x-1)^2 = 9

(x-1) = 3 or -3

Thus, x = 4 OR -2.
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Re: If ((x^2 – 2x – 2)/2) = 3, what is the one possible value of [#permalink]  03 May 2013, 23:13
1
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\frac{x^2 - 2x - 2}{2}=3

x^2- 2x - 2=6
x^2 - 2x - 8=0
(x-4)(x+2)=0

Possible solutions x=-2 or x=4
C
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Re: If ((x^2 – 2x – 2)/2) = 3, what is the one possible value of [#permalink]  03 May 2013, 23:25
Zarrolou wrote:
\frac{x^2 - 2x - 2}{2}=3

x^2- 2x - 2=6
x^2 - 2x - 8=0
(x-4)(x+2)=0

Possible solutions x=-2 or x=4
C

Thanks for the help vinaymimani & Zarrolou!

I was mistakenly adding the 6 to the -2 instead of subtracting, so I kept getting x^2 - 2x + 4.. thereby making the problem way more complex than needed, lol. It must have been late!

Appreciate the quick followups,

~ Im2bz2p345
Re: If ((x^2 – 2x – 2)/2) = 3, what is the one possible value of   [#permalink] 03 May 2013, 23:25
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