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If x/2=3/y is x<y? st 1 y> or equal to 3 st2 y< or

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If x/2=3/y is x<y? st 1 y> or equal to 3 st2 y< or [#permalink] New post 05 Dec 2005, 11:53
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:) If x/2=3/y is x<y?


st 1 y> or equal to 3

st2 y< or equal to 4


Plz explain your approach

thanks
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 [#permalink] New post 05 Dec 2005, 12:29
I think it's A

if you cross multiply you'll get xy=6

with #1) we know that y >= 3 so x must be <=2 in order to get 6 = suff.
with #2) we know that y<= 4, which means y could be 3, and x could be 2, OR y could be 1, then x would equal six. - Insuff.

So I think it's A.
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Re: DS OG 1O TH 265 [#permalink] New post 05 Dec 2005, 20:38
mand-y wrote:
:) If x/2=3/y is x<y?


st 1 y> or equal to 3

st2 y< or equal to 4


Plz explain your approach

thanks


Answer is A

If x/2=3/y, 6 = xy, is x<y?

(1) y ≥ 3 ==> x ≤ 2 ==> x < y. Sufficient
(2) y ≤ 4 ==> x ≥ 1.5 ==> x could be 3, y could be 2. x could be 2, y could be 3. Insufficient
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Re: DS OG 1O TH 265 [#permalink] New post 05 Dec 2005, 23:26
Given xy = 6.
If y = 3 then x = 2 so x < y.
So has long as y keeps increasing x should keep decreasing to maintain xy=6. Hence X< y. Stmt 1 is suff.

Stmt 2. Let y = 4 then x = 1.5 and x < y.
Let y = - 600 then x = - 1/100 and X > y. So stmt 2 insufficient.

Ans. A
Re: DS OG 1O TH 265   [#permalink] 05 Dec 2005, 23:26
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