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A) if x = 3 y is integer if x!=3 then y is not integer : so insufficient
B) if X^2 is integer then Y may or manot be integer
if X^2 is 9 then Y is integer ifX^2 != 9 not then Y is not an integer.
Combining both we cannot tell as well because X could be sqrt(3) or 3

Sorry mate. I come from computer background. x != means x not equal to. I will keep that in mind.
Yeah you are right if X were integer then C would be correct.

Moma please consider sqrt(2) and sqrt(3) also. these are not integers but the square of these is integer. So you have 4 valuse for X within the limit 1<X<4. For X = 2 and 3 the eq. is integer but for X = sqrt(2) and sqrt(3) it is not an integer.
Hence the answer is E.

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