If x= 2^b - (8^8 + 8^6), for which of the following b values is x closest to 0?
I'm happy to help with this.
Recall the exponent rule:(a^m)^n = a^(m*n)
8^8 + 8^6 = (2^3)^8 + (2^3)^6 = 2^24 + 2^18
This is the thing we want to cancel with 2^b. Well, keep in mind that 2^24 is 2^6 = 64 times larger than 2^18, so for the purposes of cancelling, we will ignore the tinier number. If we want to cancel the 2^24, we need b = 24, answer = (B)
Does all this make sense?
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