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if X^2=y+5 , y=z-2 , z=2x Is x^3 + y^2 +z divisible by 7 a)

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Senior Manager
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if X^2=y+5 , y=z-2 , z=2x Is x^3 + y^2 +z divisible by 7 a) [#permalink] New post 02 May 2007, 16:37
if X^2=y+5 , y=z-2 , z=2x
Is x^3 + y^2 +z divisible by 7

a) x>0
b) y=4

Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient
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Re: Real Hard one from GMAT Club Challenges [#permalink] New post 02 May 2007, 16:58
x^3 + (x^2-5)^2+2x = x^4 + x^3 - 10x^2 + 2x + 25 = A

(1) For x>0 there are infinite (integer) values of the expression above. Doing some calculations we have that, for x=1, A=19; x=2, A=13; x=3, A=49. So The expression could or could not be divisible by 7. Insuff =) B, C or E.

(2) y=4 =) x=3 =) The expression is divisible by 7. Suff =) B.

One thing to point out (and that I forgot to apply in this problem) is the need to start with the easiest looking btw (1) and (2). In this case, it was (2). Doing this could surely help save some precious time on exam day.


saurabhmalpani wrote:
if X^2=y+5 , y=z-2 , z=2x
Is x^3 + y^2 +z divisible by 7

(1) x>0
(2) y=4

Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient
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Re: Real Hard one from GMAT Club Challenges [#permalink] New post 02 May 2007, 17:17
Was a nice try but I think you forgot that only those values of X will be considered which satisfies X^2=Y+5

Thanks
Saurabh Malpani

Andr359 wrote:
x^3 + (x^2-5)^2+2x = x^4 + x^3 - 10x^2 + 2x + 25 = A

(1) For x>0 there are infinite (integer) values of the expression above. Doing some calculations we have that, for x=1, A=19; x=2, A=13; x=3, A=49. So The expression could or could not be divisible by 7. Insuff =) B, C or E.

(2) y=4 =) x=3 =) The expression is divisible by 7. Suff =) B.

One thing to point out (and that I forgot to apply in this problem) is the need to start with the easiest looking btw (1) and (2). In this case, it was (2). Doing this could surely help save some precious time on exam day.


saurabhmalpani wrote:
if X^2=y+5 , y=z-2 , z=2x
Is x^3 + y^2 +z divisible by 7

(1) x>0
(2) y=4

Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient
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Re: Real Hard one from GMAT Club Challenges [#permalink] New post 02 May 2007, 17:50
saurabhmalpani wrote:
if X^2 = y + 5, y = z - 2, and z = 2x,
Is x^3 + y^2 + z divisible by 7?

a) x> 0
b) y = 4


x^2 = y + 5, y = z - 2 , z = 2x
x^2 = z - 2 + 5
x^2 = 2x - 2 + 5
x^2 - 2x -3 = 0
x = -1 or 3

if x = -1, y = -4, and z = -2
if x = 3, y = 4, and z = 6


from a:
x is +ve, so x = 3.
x^3 + y^2 + z = 49. suff


from b:
y = 4 implies that x = 3.
x^3 + y^2 + z = 49. suff


So D............
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 [#permalink] New post 02 May 2007, 18:01
Great Stuff. You are right on the money!!!

OA is D.

Saurabh Malpani
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 [#permalink] New post 03 May 2007, 07:52
To Himalayan
Thanks for explanation
It makes sense now.
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Re: Real Hard one from GMAT Club Challenges [#permalink] New post 03 May 2007, 09:35
Thanks Himalaya. You turned a difficult question into a simple and easily- understood form.
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 [#permalink] New post 03 May 2007, 16:42
Great Stuff Himalayan. Thanks
  [#permalink] 03 May 2007, 16:42
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