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# If x=3/4 and y=2/5, what is the value of sqrt(x^2 + 6x + 9)

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CEO
Joined: 21 Jan 2007
Posts: 2760
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Kudos [?]: 390 [0], given: 4

If x=3/4 and y=2/5, what is the value of sqrt(x^2 + 6x + 9) [#permalink]  11 Dec 2007, 13:56
If x=3/4 and y=2/5, what is the value of sqrt(x^2 + 6x + 9) - sqrt (y^2 -2y + 1)?

87/20
63/20
47/20
15/4
14/5
CEO
Joined: 17 Nov 2007
Posts: 3574
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 414

Kudos [?]: 2245 [0], given: 359

Expert's post
B

√(x²+6x+9) - √ (y²-2y+1) = √(x+3)² - √ (y-1)²=|x+3| - |y-1| =

= |3/4+3| - |2/5-1| = 15/4 - 3/5 = (75 - 12)/20 = 63/20
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