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I am not sure if I follow the logic given in the OA.

Hi Pikachu

i guess u might have missed Zero while solving hence u wer doubting the OA. Zero is the least multiple of all the number as 1 is the least factor.....A very important point to note Consider this question :- What is the least value of a number that when divided by 3 leaves a remainder of 1?

I am not sure if I follow the logic given in the OA.

Hi Pikachu

i guess u might have missed Zero while solving hence u wer doubting the OA. Zero is the least multiple of all the number as 1 is the least factor.....A very important point to note Consider this question :- What is the least value of a number that when divided by 3 leaves a remainder of 1?

Hi Bunuel, Archit143,

When you say Zero is the least multiple of all the number, I am not following it. Anything multiplied by ZERO would result in ZERO then how come it can be a multiple. I guess I am missing something here... a property or a basic stuff. Can you please clear it out

I am not sure if I follow the logic given in the OA.

Hi Pikachu

i guess u might have missed Zero while solving hence u wer doubting the OA. Zero is the least multiple of all the number as 1 is the least factor.....A very important point to note Consider this question :- What is the least value of a number that when divided by 3 leaves a remainder of 1?

Hi Bunuel, Archit143,

When you say Zero is the least multiple of all the number, I am not following it. Anything multiplied by ZERO would result in ZERO then how come it can be a multiple. I guess I am missing something here... a property or a basic stuff. Can you please clear it out

An integer \(a\) is a multiple of an integer \(b\) (integer \(a\) is a divisible by an integer \(b\)) means that \(\frac{a}{b}=integer\): so, as 0 divided by any integer (except zero itself) yields an integer then zero is a multiple of every integer (except zero itself).

Re: If |x| < 4, what is the value of x? [#permalink]

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16 Mar 2014, 03:26

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Re: If |x| < 4, what is the value of x? [#permalink]

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12 Jun 2016, 03:32

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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