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# If |x| > 5 , is |x-5| = 5-x (1) -x(x^2) > 0

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If |x| > 5 , is |x-5| = 5-x (1) -x(x^2) > 0 [#permalink]

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07 Aug 2010, 17:57
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83% (02:20) correct 17% (00:00) wrong based on 6 sessions

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If $$|x| > 5$$, is $$|x-5| = 5-x$$

(1) $$-x(x^2) > 0$$
(2) $$x^5 < 0$$

I solved this problem and ended up with a different answer. I believe the correct answer should be E.

Any thoughts ???
[Reveal] Spoiler: OA

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07 Aug 2010, 18:31
ezhilkumarank wrote:
If $$|x| > 5$$, is $$|x-5| = 5-x$$

(1) $$-x(x^2) > 0$$
(2) $$x^5 < 0$$

I solved this problem and ended up with a different answer. I believe the correct answer should be E.

Any thoughts ???

Why do you think it should be E?
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07 Aug 2010, 19:22
I think it is D. The question is basically if x < 0 i.e x is negative. Either A or B tells us x is negative.

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07 Aug 2010, 23:55
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ezhilkumarank wrote:
If $$|x| > 5$$, is $$|x-5| = 5-x$$

(1) $$-x(x^2) > 0$$
(2) $$x^5 < 0$$

I solved this problem and ended up with a different answer. I believe the correct answer should be E.

Any thoughts ???

For $$|x-5| = 5-x$$, it is required that x-5<0 >>> x < 5

From 1 : x^2 is always positive, so -x needs to be positive , so that $$-x(x^2) > 0$$. Therefore x is a negative number, Also from the question $$|x| > 5$$, So x < - 5. SUFFICIENT

From 2 : x^5 is negative, so x needs to be negative, Also from the question $$|x| > 5$$, So x < -5. SUFFICIENT

it's D
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08 Aug 2010, 01:02
Feel the same: D.
Both 1) and 2) tell x<0.
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08 Aug 2010, 10:58
Quote:
ezhilkumarank wrote:
If |x| > 5, is |x-5| = 5-x

(1) -x(x^2) > 0
(2) x^5 < 0

I solved this problem and ended up with a different answer. I believe the correct answer should be E.

Any thoughts ???

Why do you think it should be E?

My bad. I misinterpreted the question.

From the question, $$|x|>5$$, I interpreted that x should be strictly less than -5 to satisfy the condition -- $$Is |x-5| = 5 - x$$.

But the two answer options note that x is negative but not strictly less than -5 hence I thought option E is the correct.
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31 Oct 2010, 21:28
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+1 D
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Re: Inequalities question.   [#permalink] 31 Oct 2010, 21:28
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