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If x and y are consecutive negative integers, is x greater

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If x and y are consecutive negative integers, is x greater [#permalink] New post 04 Aug 2010, 21:58
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If x and y are consecutive negative integers, is x greater than y?

(1) x + 1 and y – 1 are consecutive negative integers.
(2) x is an even integer.
[Reveal] Spoiler: OA

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Last edited by aiming4mba on 04 Aug 2010, 22:18, edited 1 time in total.
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Re: DS question [#permalink] New post 04 Aug 2010, 22:51
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aiming4mba wrote:
If x and y are consecutive negative integers, is x greater than y?
a. x + 1 and y – 1 are consecutive negative integers.
b. x is an even integer.


x and y are consecutive integers means that either:
y=x+1 (for example x=-5 and y=-4), in this case x<y;
OR:
x=y+1 (for example x=-5 and y=-6), in this case x>y.

So the we should determine which case we have.

(1) x+1 and y-1 are consecutive negative integers --> again either x+1=(y-1)+1 --> x+1=y (first case so x<y) or y-1=(x+1)+1 --> y=x+3, which is not possible as x and y are consecutive integers (difference between two consecutive integers can not equal to 3). So only first case is possible: x<y. Sufficient.

(2) x is an even integer. Clearly insufficient.

Answer: A.
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Re: DS question   [#permalink] 04 Aug 2010, 22:51
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