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If x and y are consecutive positive iteger multiple of 3,

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If x and y are consecutive positive iteger multiple of 3, [#permalink] New post 07 Sep 2005, 04:24
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If x and y are consecutive positive iteger multiple of 3, what is the greatest integer J such that XY/J is always an iteger?
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 [#permalink] New post 07 Sep 2005, 09:17
I agree, smallest number is 18 (3*6).
Then after those 2 first numbers all 2 consecutive multiples of 3 will be formed by :
- a multiple of 3 (odd)
- a multiple of 2 and 3 so always a mutliple of 6 (even)

so definitely divisible by 18
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 [#permalink] New post 07 Sep 2005, 09:23
18 for me and this is how I would do it...

so we have x=3m
and y=3n

y*x=9 m*n

so J has to be J= A*9 M*N

so lets look at multiples of 3, say 3 and 6

prime factors are 3, 3, 2, so we got 3^2*9 as the largest factor for which all consecutive multiples of 3 will be divisible by...

18 it is..
  [#permalink] 07 Sep 2005, 09:23
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If x and y are consecutive positive iteger multiple of 3,

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