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if x and y are integers and x<y, what is the value of x+y?

1. x^y=4 2. x absolute = y absolute

it seems weird as obviously the only y that there is not Y which is less than X that satisfies either/both 1 and 2.....

Good question.

If x and y are integers and x<y, what is the value of x+y?

(1) x^y=4 --> as x and y are integers and x<y then only possible solution is (-2)^2=4 (other integer solutions for x^y=4 are: 2^2=4 and 4^1=4) --> x+y=-2+2=0. Sufficient.

(2) |x|=|y| --> as also x<y then they have opposite signs (x<0<y, so |x|=-x and|y|=y) --> -x=y --> x+y=0. Sufficient.

If x and y are integers and x < y, what is the value of x + y?

(1) x^y = 4

(2) |x| = |y|

Edited for typo

The question has very simple fundamentals but it is still tricky, mainly because it gives you a part of the information in the question stem. We often forget to consider that when we are busy analyzing the statements.

x and y are integers x < y Question: (x + y) = ?

(1) x^y = 4 This can happen in a number of ways: x= 2, y = 2 x = -2, y = 2 x = 4, y = 1 But in only one case, x < y. x must be -2 and y must be 2. x + y = 0 Sufficient

(2) |x| = |y| This can happen in two ways: x = y (x and y have same sign and absolute value) or x = -y (x and y have opposite signs and same absolute value) Since x < y, x must be negative and y must be positive. (they both cannot be positive since their absolute value is the same but x < y) In that case x = -y x+y = -y+y = 0 Sufficient

Re: If x and y are integers and x<y, what is the value of x+y? [#permalink]

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25 Dec 2014, 10:09

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