If x and y are integers and y=l x+3 l + l 4-x l, does y=7? : DS Archive
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# If x and y are integers and y=l x+3 l + l 4-x l, does y=7?

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If x and y are integers and y=l x+3 l + l 4-x l, does y=7? [#permalink]

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06 May 2006, 08:27
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If x and y are integers and y=l x+3 l + l 4-x l, does y=7?
1)x<4
2)x>-3
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06 May 2006, 09:09
If x and y are integers and y=l x+3 l + l 4-x l, does y=7?
1)x<4
2)x>-3

Y will be seven only if:
[x+3]=x+3 --> so x should be greater than -3

and

[4-x]=4-x. --> x should be less 4

Combining both we get -3<x<4

Hence C.
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06 May 2006, 15:38
y = 7 if x > -3 and x < 4. A and B cannot individually cater to the complete condition. So C.
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Thanks,
Zooroopa

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06 May 2006, 17:10
Agree with C
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18 Jun 2006, 19:28
-3<x<4 is the final inequality which satisfies the equation. Hence C.

None of the individual statements are suff.
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18 Jun 2006, 20:43
St1:
insufficient. If x = 3, y = 6 + 1 = 7. If x = -5, y = 2 + 9 = 11.

St2:
insufficient. If x = 2, y = 5 + 2 = 7. If x = 5, y = 8 + 1 = 9.

Using st1 and st2:
-3 < x < 4 --> legal values of x = -2,-1,0,1,2,3

All these values of x gives y = 7. Sufficient.

Ans C
18 Jun 2006, 20:43
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