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If x and y are integers between 10 and 99, inclusive, is [#permalink]
16 Nov 2006, 12:12

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Difficulty:

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Question Stats:

100% (02:11) correct
0% (00:00) wrong based on 0 sessions

24. If x and y are integers between 10 and 99, inclusive, is (x-y)/9 an integer?

(1) x and y have the same two digits, but in reverse order.
(2) The tensâ€™ digit of x is 2 more than the units digit, and the tens digit of y is 2 less than the units digit.

24. If x and y are integers between 10 and 99, inclusive, is (x-y)/9 an integer?

(1) x and y have the same two digits, but in reverse order.
(2) The tensâ€™ digit of x is 2 more than the units digit, and the tens digit of y is 2 less than the units digit.

From the stem we can see that 0=<(x-y)=<89
From 1 we get:

AB-BA = a multiple of 9 for (x-y)/9 to be an integer. Plugging in any numbers relevant to the stem for this starting with x=1 and y=1, and its clear that the difference between AB-BA is a multiple of 9. SUFF

2) doesn't give us enough. Say x could be 42 and y could be 24, this would be suff. But if x is 86 and y is 35 its insuff.

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