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If x and y are integers, is x > y?

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If x and y are integers, is x > y? [#permalink] New post 07 Dec 2012, 07:48
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If x and y are integers, is x > y?

(1) x + y > 0
(2) y^x < 0
[Reveal] Spoiler: OA
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Re: If x and y are integers, is x > y? [#permalink] New post 07 Dec 2012, 07:55
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If x and y are integers, is x > y?

(1) x + y > 0. Given that the sum of two numbers is greater than zero, but we cannot determine which one is greater. Not sufficient.

(2) y^x < 0. This statement implies that y is a negative number. Now, if y=-1 and x=1, then x>y BUT if y=-1 and x=-1, then x=y. Not sufficient.

(1)+(2) Since from (2) we have that y is a negative number, then -y is a positive number. Therefore from (1) we have that x>-y=positive, which means that x is a positive number. So, we have that x=positive>y=negative. Sufficient.

Answer: C.
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Re: If x and y are integers, is x > y? [#permalink] New post 08 Oct 2013, 08:29
Bunuel wrote:
If x and y are integers, is x > y?

(1) x + y > 0. Given that the sum of two numbers is greater than zero, but we cannot determine which one is greater. Not sufficient.

(2) y^x < 0. This statement implies that y is a negative number. Now, if y=-1 and x=1, then x>y BUT if y=-1 and x=-1, then x=y. Not sufficient.

(1)+(2) Since from (2) we have that y is a negative number, then -y is a positive number. Therefore from (1) we have that x>-y=positive, which means that x is a positive number. So, we have that x=positive>y=negative. Sufficient.

Answer: C.



Should the answer not be E ?

My explanation as followa

Case 1 :
-2>-5 Stmt 1 correct

(-5)^(-2) < 0

(1/25) < 0 Stmt 2 correct

-2 > 5 No ( Is x > y ? )

Case 2 :

5 > -2 Stmt 1 correct

(5) ^ (-2 )< 0

(1/25 ) < 0 Stmt 2 correct

5 > 2 Yes ( Is x > y ? )
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Re: If x and y are integers, is x > y? [#permalink] New post 08 Oct 2013, 16:12
shelrod007 wrote:
Bunuel wrote:
If x and y are integers, is x > y?

(1) x + y > 0. Given that the sum of two numbers is greater than zero, but we cannot determine which one is greater. Not sufficient.

(2) y^x < 0. This statement implies that y is a negative number. Now, if y=-1 and x=1, then x>y BUT if y=-1 and x=-1, then x=y. Not sufficient.

(1)+(2) Since from (2) we have that y is a negative number, then -y is a positive number. Therefore from (1) we have that x>-y=positive, which means that x is a positive number. So, we have that x=positive>y=negative. Sufficient.

Answer: C.



Should the answer not be E ?

My explanation as followa

Case 1 :
-2>-5 Stmt 1 correct

(-5)^(-2) < 0

(1/25) < 0 Stmt 2 correct

-2 > 5 No ( Is x > y ? )

Case 2 :

5 > -2 Stmt 1 correct

(5) ^ (-2 )< 0


(1/25 ) < 0 Stmt 2 correct

5 > 2 Yes ( Is x > y ? )


(-5)^(-2)=\frac{1}{25} also 1/25>0

Remember when you square a negative number you get a positive number.


(5)^-2=\frac{1}{25}, and again \frac{1}{25}>0 not less

when you have X^-Y, it's written out as \frac{1}{(X^Y)}
Re: If x and y are integers, is x > y?   [#permalink] 08 Oct 2013, 16:12
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