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I. x when divided by 2y leaves a remainder of 4.
x = 2yK1 + 4
we can't say what remainder we get when x is divided by y with this info
II. x+y when divided by y leaves a remainder of 4.
This remainder (4) will be exactly same remainder as when x is divided by y.
x+y = yK2 + 4
x = y(K2-1) + 4 -> this is eqn for X divided by Y
=> same remainder 4
however I am totally lost with the second statement MA, if you can develop your choice please...
from ii,
if 4 is reminder when X+Y is divided by Y, then 4 is reminder when X divided by Y because Y divided by Y remains 0 as reminder. it is X when divided by Y remains 4 as reminder.............
however I am totally lost with the second statement MA, if you can develop your choice please...
from ii,
if 4 is reminder when X+Y is divided by Y, then 4 is reminder when X divided by Y because Y divided by Y remains 0 as reminder. it is X when divided by Y remains 4 as reminder.............
MA,
Will it be the same "if x+y when divided by x leaves a remainder of 4. "
however I am totally lost with the second statement MA, if you can develop your choice please...
from ii,
if 4 is reminder when X+Y is divided by Y, then 4 is reminder when X divided by Y because Y divided by Y remains 0 as reminder. it is X when divided by Y remains 4 as reminder.............
==> x=y(2k)+4 so x/y also leaves a remainder of 4 (Only the quotient changes)
(II) ==> x+y=yk + 4 ==> x=y(k-1) + 4 again x/y leaves a remainder of 4.
So D.
Anirban
That's not correct for the I statement, say x = 12 and y = 4....remainder is 0....but x/2y leaves a remainder of 4. One has to represent the eqn in multipliers of y i.e. y+y, y+2y,y+3y.....and y(k-1) represents that and not y(2k)
y is not necessarily 4 either, could be x+4, 2x+4, etc.
honghu,
you did not notice Folaa3's posting. my posting is in response to his/her posting "Will it be the same "if x+y when divided by x leaves a remainder of 4."