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If x and y are nonzero integers, what is the remainder when

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Manager
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If x and y are nonzero integers, what is the remainder when [#permalink] New post 23 Sep 2011, 16:52
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If x and y are nonzero integers, what is the remainder when x is divided by y ?

(1) When x is divided by 2y, the remainder is 4.

(2) When x + y is divided by y, the remainder is 4.
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Re: DS - remainder [#permalink] New post 23 Sep 2011, 23:20
bschool83 wrote:
If x and y are nonzero integers, what is the remainder when x is divided by y ?

(1) When x is divided by 2y, the remainder is 4.

(2) When x + y is divided by y, the remainder is 4.


I will go for B on this one ...

St1: let X = 4 Y = 4 then
x/2y R = 4.... X/Y R = 1
let X = 4 Y= 5
x/2y R = 4 ...X/Y R = 4................... Insufficient

St2:

X+y/y R = 4

X = 9 ; Y = 5 X+y/y R = 4 and X/y R = 4
X = 4 Y = 16 X+Y/Y R = 4 and X/Y R = 4..

Holds good .. sufficient
Hence B
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Re: DS - remainder [#permalink] New post 24 Sep 2011, 04:50
bschool83 wrote:
If x and y are nonzero integers, what is the remainder when x is divided by y ?

(1) When x is divided by 2y, the remainder is 4.

(2) When x + y is divided by y, the remainder is 4.


bschool83:
Please search a question before so as to avoid reposting.
ds-what-is-the-remainder-when-x-is-divided-by-y-66538.html

How to search:
common-posting-ethics-119627.html
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Kudos [?]: 9 [0], given: 12

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Re: DS - remainder [#permalink] New post 25 Sep 2011, 04:18
bschool83 wrote:
If x and y are nonzero integers, what is the remainder when x is divided by y ?

(1) When x is divided by 2y, the remainder is 4.

(2) When x + y is divided by y, the remainder is 4.


1. is insufficient
2. Sufficient
Answer should be B.
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Re: DS - remainder [#permalink] New post 25 Sep 2011, 05:14
Good one Sudhir...You seem to be a maths champ :)
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Kudos [?]: 33 [0], given: 43

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Re: DS - remainder [#permalink] New post 26 Sep 2011, 04:16
IMO B.

Time taken: 2 min 4 secs
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Kudos [?]: 34 [0], given: 123

Re: DS - remainder [#permalink] New post 27 Sep 2011, 01:36
Same here, i took more than 2 mins to solve it..... :(
Re: DS - remainder   [#permalink] 27 Sep 2011, 01:36
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