If X and Y are nonzero integers, what is the remainder when : DS Archive
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# If X and Y are nonzero integers, what is the remainder when

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If X and Y are nonzero integers, what is the remainder when [#permalink]

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26 Oct 2005, 06:48
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If X and Y are nonzero integers, what is the remainder when X/Y?

1. When X/2Y, the remainder is 4.
2. When X+Y is divided by Y, the remainder is 4
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26 Oct 2005, 08:05
1. When X/2Y, the remainder is 4.

>> Insuff.
>> Assume X = 28 and Y = 3 => Remainder of X/2Y = 4. But X/Y = 1
>> Assume X = 28 and Y = 4 => Remainder of X/2Y = 4. But X/Y = 0

2. When X+Y is divided by Y, the remainder is 4

>> Suff.
>> (x+y)/y => x/y + y/y
>> y evenly divides itself. Hence X/Y remainder is 4.

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26 Oct 2005, 11:32
X/Y = 3

(X+Y)/Y = 4;

X/Y + 1 = 4;

Ans:X/Y = 3
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26 Oct 2005, 15:36
I see how 1 is insufficient but can someone explain (again) how 2 is sufficient?

(x+y)/y = R4

This statement simplified is x/y + y/y = R4

Now where do we go from here?
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26 Oct 2005, 15:39
ValleyBall1 wrote:
I see how 1 is insufficient but can someone explain (again) how 2 is sufficient?

(x+y)/y = R4

This statement simplified is x/y + y/y = R4

Now where do we go from here?

That is the solution.. y/y leaves no reminder... and then x/y leaves 4.... which is exactly what the stem was asking.
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26 Oct 2005, 15:56
Duh...that's why I'm not doing too well on DS. When I think the question is tricking me, it isn't. When I think the question is straightforward, it tricks me. Urghh
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27 Oct 2005, 07:31
OA is B. OE is a full page long, but Suhagar summarized it pretty well.
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27 Oct 2005, 08:34
sudhagar wrote:
1. When X/2Y, the remainder is 4.

>> Assume X = 28 and Y = 4 => Remainder of X/2Y = 4. But X/Y = 0

28/(4*2) =7/2 => remainder is 1
27 Oct 2005, 08:34
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