Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Seems like a straight forward problem, however the answer choices are a little confusing .

both D& E seem to be contendors for the right answer though the OA is D

D-> Because the sum of two perfect square needn't necessarily be a perfect square e.g 4+9=13, not a perfect square, however 9 & 16 = 25 which is a perfect square) E-> Because a perfect square to the power 5 (an ODD number) cannot be a perfect square right ?

Re: If X & Y are perfect squares, then which one of the [#permalink]
05 Jun 2012, 02:57

x = a^2 y = b^2

a) (a^2)^2, ok b) a^2 * b^2 = (ab)^2, ok c) 4*a^2 = 2^2*a^2 = (2a)^2, ok d) a^2 + b^2, clearly not ok for all a/b, e.g a = 8, b = 2, 64 + 4 = 68 which is not a perfect square. e) (a^2)^5 = (a^5)^2, ok

Re: If x and y are perfect squares, then which one of the [#permalink]
22 Apr 2013, 23:31

sdas wrote:

Option B is not clear to me.... X=a^2 Y=b^2

Therefore X*Y = (ab)^2 But, if x=4 and y=9 , then xy=25 However, if x= 4 and y = 25, then xy = 100 which is not perfect square

So, how can we rule out B?

Please explain

If x=4 and y=9 xy =36 which is a perfect square. and xy=100 is a perfect square. its the square of 10. for that matter , product of any two perfect squares is a perfect square. as you pointed out (ab)^2. so square root of the product is ab an integer.

Seems like a straight forward problem, however the answer choices are a little confusing .

both D& E seem to be contendors for the right answer though the OA is D

D-> Because the sum of two perfect square needn't necessarily be a perfect square e.g 4+9=13, not a perfect square, however 9 & 16 = 25 which is a perfect square) E-> Because a perfect square to the power 5 (an ODD number) cannot be a perfect square right ?

Please explain.

Thanks, Shreya

If x=y=1^2=1, then each option but D is a perfect square, therefore D is NOT necessarily a perfect square.

Answer: D.

P.S. Notice that x+y could be a perfect square for example if x=3^2=9 and y=4^2=16 --> x+y=25=5^2. _________________

Low GPA MBA Acceptance Rate Analysis Many applicants worry about applying to business school if they have a low GPA. I analyzed the low GPA MBA acceptance rate at...

UNC MBA Acceptance Rate Analysis Kenan-Flagler is University of North Carolina’s business school. UNC has five programs including a full-time MBA, various executive MBAs and an online MBA...

To hop from speaker to speaker, to debate, to drink, to dinner, to a show in one night would not be possible in most places, according to MBA blogger...

Most top business schools breed their students for a career in consulting or financial services (which is slowly being displaced by high tech and entrepreneurial opportunities). Entry into...