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If x and y are positive integers and x is a multiple of y,

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If x and y are positive integers and x is a multiple of y, [#permalink] New post 06 May 2006, 01:07
. If x and y are positive integers and x is a multiple of y, is y = 2?
(1) y ≠ 1
(2) x + 2 is a multiple of y.
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 [#permalink] New post 06 May 2006, 01:24
Answer is C

Given:
x=ny

1-> Tell us NOthing!

2->
x+2 = my
or, ny + 2 = my
or 2 = (m-n)y
So y = 1 or 2!

Combining:
y is not 1... So y =2!
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 [#permalink] New post 20 Jun 2006, 22:44
Agree with the explanation.
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 [#permalink] New post 24 Jun 2006, 01:18
sm176811 wrote:
2 = (m-n)y
So y = 1 or 2!



Pardon me for the silly question, but how do you get
y=1 or 2 from 2=(m-n)y ?


Thanks in advance
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 [#permalink] New post 24 Jun 2006, 10:11
Correct Answer...

2 = (m - n)*y => m and n are integers, and y ≠ 1, so y has to be 2!
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 [#permalink] New post 24 Jun 2006, 10:21
yeah looks like C -

1) is insuff because y could be anything other then 1

2)is insuff because y could be 1 or 2

Combined you know y cant be 1 so it must be 2.
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 [#permalink] New post 25 Jun 2006, 16:10
C.

Quote:
Pardon me for the silly question, but how do you get
y=1 or 2 from 2=(m-n)y ?


Since y is integer, y =2/(m-n) will be integer only when (m-n) = 1 or 2.

Hence y =1,2
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  [#permalink] 25 Jun 2006, 16:10
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