ajit257 wrote:

If x and y are positive integers and \(y=\sqrt{9 - x}\), what is the value of y?

(1) x < 8

(2) y > 1

For the given expression we have x,y are positive integers and therefore squaring both sides

y^2= 9-x

From St 1 we have x< 8 -----> so we have possible value of in the range 0<x<8

Only for x=5, we have y=2

So options B,C and E ruled out

St 2 says y>1 so we have y^2=9-x

Now let us say y=2 so x=5

y=3, we get 9=9-x ----> x=0 which is not possible as "x" is a positive integer

hence y=2

Ans should be D

I messed it with choosing A as ans trying to beat the average time and not carefully solving the st2

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