Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Lemme verify my procedure here! According to the post, for x/y being a proper fraction will go closer to a/b if the operation x+a/y+b is performed. And as always \(x/y < x+a/y+b\). The values still go closer to 1 for improper fraction but, \(x/y > x+a/y+b\)!

So, by combining both the statements we confirm that x/y is always less than 5/20 i.e. 1/4 and Hence a proper fraction. Hence if I am to add 2 in the numerator and 3 to the denom, the fraction will approach 2/3. Hence the answer derived, \(x+2/y+93 > x/y\):) *Please correct me If I am wrong *

Def better than the plug and chug would have taken me a long time to figure this one out by the normal way Wonderful method Mike!

Re: If x and y are positive integers, is [#permalink]
15 May 2013, 03:06

Expert's post

madzstar wrote:

a= statment 1 alone sufficient

b= statment 2 alone is sufficient

c= both statments together are sufficient

d= both statment together are insufficient

e= none of the above

right? am i right will all of the following cause i end up guessing alot

The data sufficiency problem consists of a question and two statements, labeled (1) and (2), in which certain data are given. You have to decide whether the data given in the statements are sufficient for answering the question. Using the data given in the statements, plus your knowledge of mathematics and everyday facts (such as the number of days in July or the meaning of the word counterclockwise), you must indicate whether—

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked. C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked. D. EACH statement ALONE is sufficient to answer the question asked. E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed. _________________

Re: If x and y are positive integers, is [#permalink]
16 Dec 2014, 14:05

1

This post received KUDOS

1

This post was BOOKMARKED

If x and y are positive integers, is \frac{x}{y}<\frac{x+2}{y+3}? Statement #1: y > 20 Statement #2: x < 5

solution:

since x and y are positive, then we can cross multiply the questions:

is x(y+3) < y(x+2)? is xy+3x < xy + 2y? is 3x<2y? is 3x-2y<0?

basically the question is asking if x<y?

from the statements, none is sufficient to answer the question alone. combining the two, we can conclusively conclude that x < y. therefore answer is 'C'

Give kuddos if you like my explanation!

gmatclubot

Re: If x and y are positive integers, is
[#permalink]
16 Dec 2014, 14:05

Back to hometown after a short trip to New Delhi for my visa appointment. Whoever tells you that the toughest part gets over once you get an admit is...