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If X and Y are positive integers, what is the remainder of

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If X and Y are positive integers, what is the remainder of [#permalink] New post 18 Dec 2007, 10:25
If X and Y are positive integers, what is the remainder of (XY)/4?

remainder of x/4 is 3
remainder of y/4 is 2
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 [#permalink] New post 18 Dec 2007, 11:02
From 1: x = 3, 7, 11, 15, 19, 23
From 2: y = 2, 6, 10, 14, 18, 22

any number from the X list multiplied by any number from the Y list will result in a remainder of 2 when divided by 4.

I'll go with C.
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 [#permalink] New post 18 Dec 2007, 11:03
How did you combine the statements?
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 [#permalink] New post 18 Dec 2007, 12:05
Expert's post
C

x=4n+3
y=4m+2

xy=16nm+8n+12m+6=4*(4nm+2n+3m+1)+2
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 [#permalink] New post 18 Dec 2007, 13:28
From STMT 1: X = 7, 11, 15 etc
From STMT 2: Y = 6, 10, 14 etc

each statement by itself is insufficient but combining both gives remainder as 2. So C.
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 [#permalink] New post 18 Dec 2007, 13:36
bmwhype2 wrote:
How did you combine the statements?


3*2 / 4 = 6/4 = R2

OA is C
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Re: remainders [#permalink] New post 18 Dec 2007, 15:20
bmwhype2 wrote:
If X and Y are positive integers, what is the remainder of (XY)/4?

remainder of x/4 is 3
remainder of y/4 is 2


C the remainder is always 2.
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 [#permalink] New post 18 Dec 2007, 19:32
Late, but C:

I. Insuff: x/4 --> R=3, it means that x = 3, 3+4 = 7, 7+4 = 11 and so on
II. Insuff: y/x --> R=2 means that y = 2, 2+4 = 6 ans do on

Together: 3*2 / 4 --> R=2, 2*6 / 4 --> R=2 --> Suff
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 [#permalink] New post 18 Dec 2007, 20:48
late, but went for C. each statement alone doesnt tell us about the other, and together, remainder is always two. Approach same as walkers
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 [#permalink] New post 18 Dec 2007, 21:46
walker wrote:
C

x=4n+3
y=4m+2

xy=16nm+8n+12m+6=4*(4nm+2n+3m+1)+2


I go with C, and explaination is the same as Walker's
  [#permalink] 18 Dec 2007, 21:46
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